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2 years ago

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WHAT IS THE ANSWER OF A VOLUME OF A CYLINDER WITH A DIAMETER OF 6CM AND HEIGHT OF 12CM

1 answer:

zloy xaker [14]2 years ago

6 0

Answer:

339.3

Step-by-step explanation:

V=πr2h=π·32·12≈339.29201

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Himari is solving the equation 4 ( x - 3 ) = 16. Her first step is 4x - 12 = 16. Which step could be the next step? Select all t

Pani-rosa [81]

Answer:

Her next step would be to add 12 to both sides of the equation

Step-by-step explanation:

Which would make the equation 4x=28

Then you divide both sides by 4 giving you x=7

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3 years ago

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Simplify using only POSITIVE exponents:

pickupchik [31]

So here are a few rules with exponents that you should know:

Multiplying exponents of the same base: $x^m*x^n=x^{m+n}$
Dividing exponents of the same base: $x^m\div x^n=x^{m-n}$
Powering a power to a power: $(x^m)^n=x^{m*n}$
Converting a negative exponent to a positive one: $x^{-m}=\frac{1}{x^m}\ \textsf{and}\ \frac{1}{x^{-m}}=x^m$

<h2>1.</h2>

Firstly, solve the outside exponent:

$(2x^3y^7)^{-2}=2^{-2}x^{3*-2}y^{7*-2}=2^{-2}x^{-6}y^{-14}$

Next, convert the negative exponents into positive ones:

$2^{-2}x^{-6}y^{-14}=\frac{1}{2^2x^6y^{14}}=\frac{1}{4x^6y^{14}}$

<u>Your final answer is $\frac{1}{4x^6y^{14}}$ </u>

<h2>2.</h2>

For this, just divide:

$\frac{12x^5y^3}{4x^{-1}}=\frac{12}{4}x^{5-(-1)}y^{3-0}=3x^6y^3$

<u>Your final answer is $3x^6y^3$ </u>

<h2>3.</h2>

For this, convert all negative exponents into positive ones:

$\frac{r^{-7}b^{-8}}{t^{-4}w}=\frac{t^4}{r^7b^8w}$

<u>Your final answer is $\frac{t^4}{r^7b^8w}$ </u>

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3 years ago

What is 63.48 rounded off to 1 decimal place?

Lilit [14]

Answer:

63.5

Step-by-step explanation:

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3 years ago

If they have 40 packages of soap, how much liters will they need?

Amiraneli [1.4K]

40 x 100L which is wrong but i need points

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3 years ago

Solve John bakes 147 donuts in 7 batches. How many does each batch contain?

lys-0071 [83]

You can solve this by dividing the baches into the total amount of donuts.

147/7=21

Each batch has 21 donuts.

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3 years ago

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