Answer:
d. d1− = 10, d1+ = 0
Explanation:
Given
3X1 + 4X2 +d1− − d1+ = 36
X1 = 6
X2 = 2
Required
Possible values of d1- and d1+
We have:
3X1 + 4X2 +d1− − d1+ = 36
Substitute values for X1 and X2
3 *6 + 4 * 2 + d1- - d1+ = 36
18 + 8 + d1- - d1+ = 36
Collect like terms
d1- - d1+ = 36 - 18 - 8
d1- - d1+ = 10
For the above equation to be true, the following inequality must be true
d1- > d1+
Hence,
(d) is correct
Because:
10 > 0
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