You can compress them. ZIP is the most well known protocol.
Answer:
Mohammed doesn't believe the cyberbullying exists.
Explanation:
If he knew he wouldn't say they are teasing him. I mean, how would their parents know he is being cyberbullied without evidence? Text messages(such as imessages) are most likely on phones, and not on computers.(Unless its an mac I believe.) And they are bullying him; its not using technology positively.
Answer: Opportunity for Improvement
Explanation:
Any healthcare organization, service, or process that does not reach the established standard or the customer's expectations, is an opportunity for improvement. Furthermore, the Improving Medicare Post-Acute Care Transformation Act (IMPACT) established a quality reporting program aimed to find those opportunities for improvement. Once the problem has been established, is prudent to place an action plan to achieve the desired performance improvement aim.
Answer:
- public class FindDuplicate{
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
-
- int n = 5;
- int arr[] = new int[n];
-
- for(int i=0; i < arr.length; i++){
- int inputNum = input.nextInt();
- if(inputNum >=1 && inputNum <=n) {
- arr[i] = inputNum;
- }
- }
-
- for(int j =0; j < arr.length; j++){
- for(int k = 0; k < arr.length; k++){
- if(j == k){
- continue;
- }else{
- if(arr[j] == arr[k]){
- System.out.println("True");
- return;
- }
- }
- }
- }
- System.out.println("False");
- }
- }
Explanation:
Firstly, create a Scanner object to get user input (Line 4).
Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).
Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.
If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".
