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Bezzdna [24]
2 years ago
7

Complete the table for each function. Then answer the questions that follow.

Mathematics
2 answers:
givi [52]2 years ago
4 0

Answer:

Complete the table for each function.  Then answer the questions that follow.

a= 4

b = 4

c =8

d = 16

e = 12

f = 36

g = 64

Step-by-step explanation:

Edge Jan 2022

NEXT QUESTION:

 According to the table, which function grows the fastest?

The exponential function

NEXT ONE AFTER THAT:

By what factor does the y-value change for y = 4x?  

<h3> 4</h3>

NikAS [45]2 years ago
3 0

The complete value for the function is as follows:

a = 4

b = 4

c = 8

d = 16

e = 12

f = 36

g = 64

<h3>What are functions?</h3>

Function relates input to output. Function establish relationship between variables. Therefore,

The input are as follows:

  • 0
  • 1
  • 2
  • 3

Let's find the missing outputs as follows.

y₁ = 4x

  • c = 4(2) = 8
  • e = 4(3) = 12

y₂ = 4x²

  • a = 4(1)² = 4
  • f = 4(3)² = 36

y₃ = 4ˣ

  • b = 4¹ = 4
  • d = 4² = 16
  • g = 4³ = 64

learn more on function here: brainly.com/question/4117598?referrer=searchResults

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PPPLLLLEEEAASSSEEEE HHHEEEELLLLPPPPP!!!!!!!
Yuliya22 [10]

Answer:

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Step-by-step explanation:

Because the center of dilation is at (0, 0), or the origin, we can just multiply the x and y values of each point by the scale factor of 13.

(3, 3) × 13 = (39, 39)

(0, 3) × 13 = (0, 39)

(6, -6) × 13 = (78, -78)

(9, 6) × 13 = (117, 78)

Read more on Brainly.com - brainly.com/question/11445104#readmore

4 0
3 years ago
Solve for x, 12y+6=6(y+1)
Vanyuwa [196]

For this case we must solve the following equation:

12y + 6 = 6 (y + 1)

We apply distributive property on the right side of the equation:

12y + 6 = 6y + 6

We subtract 6y on both sides of the equation:

12y-6y + 6 = 6\\6y + 6 = 6

We subtract 6 from both sides of the equation:

6y = 6-6\\6y = 0

Dividing by 6 on both sides of the equation:

y = 0

So, the result is y = 0

Answer:

y = 0

4 0
3 years ago
In a dilation with a scale factor of 3/4 , the image is ___________ the pre image
adelina 88 [10]
 A is the correct choice
4 0
3 years ago
Consider the transpose of Your matrix A, that is, the matrix whose first column is the first row of A, the second column is the
Zarrin [17]

Answer:The system could have no solution or n number of solution where n is the number of unknown in the n linear equations.

Step-by-step explanation:

To determine if solution exist or not, you test the equation for consistency.

A system is said to be consistent if the rank of a matrix (say B ) is equal to the rank of the matrix formed by adding the constant terms(in this case the zeros) as a third column to the matrix B.

Consider the following scenarios:

(1) For example:Given the matrix A=\left[\begin{array}{ccc}1&2\\3&4\end{array}\right], to transpose A, exchange rows with columns i.e take first column as first row and second column as second row as follows:

Let A transpose be B.

∵B=\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]

the system Bx=0 can be represented in matrix form as:

\left[\begin{array}{ccc}1&3\\2&4\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right] ................................eq(1)

Now, to determine the rank of B, we work the determinant of the maximum sub-square matrix of B. In this case, B is a 2 x 2 matrix, therefore, the maximum sub-square matrix of B is itself B. Hence,

|B|=(1*4)-(3*2)= 4-6 = -2 i.e, B is a non-singular matrix with rank of order (-2).

Again, adding the constant terms of equation 1(in this case zeros) as a third column to B, we have B_{0}:      

B_{0}=\left[\begin{array}{ccc}1&3&0\\4&2&0\end{array}\right]. The rank of B_{0} can be found by using the second column and third column pair as follows:

|B_{0}|=(3*0)-(0*2)=0 i.e, B_{0} is a singular matrix with rank of order 1.

Note: a matrix is singular if its determinant is = 0 and non-singular if it is \neq0.

Comparing the rank of both B and B_{0}, it is obvious that

Rank of B\neqRank of B_{0} since (-2)<1.

Therefore, we can conclude that equation(1) is <em>inconsistent and thus has no solution.     </em>

(2) If B=\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right] is the transpose of matrix A=\left[\begin{array}{ccc}-4&-8\\5&10\end{array}\right], then

Then the equation Bx=0 is represented as:

\left[\begin{array}{ccc}-4&5\\-8&10&\end{array}\right]\left[\begin{array}{ccc}x_{1} \\x_{2} \end{array}\right]=\left[\begin{array}{ccc}0\\0\end{array}\right]..................................eq(2)

|B|= (-4*10)-(5*(-8))= -40+40 = 0  i.e B has a rank of order 1.

B_{0}=\left[\begin{array}{ccc}-4&5&0\\-8&10&0\end{array}\right],

|B_{0}|=(5*0)-(0*10)=0-0=0   i.e B_{0} has a rank of order 1.

we can therefor conclude that since

rank B=rank B_{0}=1,  equation(2) is <em>consistent</em> and has 2 solutions for the 2 unknown (X_{1} and X_{2}).

<u>Summary:</u>

  • Given an equation Bx=0, transform the set of linear equations into matrix form as shown in equations(1 and 2).
  • Determine the rank of both the coefficients matrix B and B_{0} which is formed by adding a column with the constant elements of the equation to the coefficient matrix.
  • If the rank of both matrix is same, then the equation is consistent and there exists n number of solutions(n is based on the number of unknown) but if they are not equal, then the equation is not consistent and there is no number of solution.
5 0
3 years ago
A circle has a circumference of 6. It has an arc of length 1.
Viktor [21]

Answer:

<h3>60°</h3>

Step-by-step explanation:

Given that:

  • Circumference (C) = 6 units
  • Arc length (A) = 1 unit

<u>Find the central angle (</u><u>θ</u><u>)</u>

Arc is some part of circumference; thus,

the equation of arc length =

A = θ/360 × C

θ/360 = A/C

θ = (360×A)/C

θ = (360×1)/6

θ = 360 ÷ 6

<h3>θ = 60° ✅</h3>

Central angle = 60°

______________

#IndonesianPride

- kexcvi

8 0
3 years ago
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