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prohojiy [21]
3 years ago
13

Aproxima a las unidades de mil y obtén los resultados estimados

Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

hi

Step-by-step explanation:

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If (x-y)^2=100 and xy=20. what's the value of x^2+y^2?
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(x-y)^2=x^2-2xy+y^2=(x^2+y^2)-2(xy)\\\\\text{We have}\ (x-y)^2=100\ \text{and}\ xy=20.\\\\\text{Substitute}\\\\100=(x^2+y^2)-2(20)\\100=(x^2+y^2)-40\qquad\text{add 40 to both sides}\\\\140=(x^2+y^2)\\\\Answer:\ \boxed{x^2+y^2=140}

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k = 9

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m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

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An x-intercept is namely a "solution" or "zero" or "root" often called, and when that happens, y = 0, just like with any other x-intercept.

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so what is its x-intercept anyway?

\bf \stackrel{y}{0}=(x-3)^2-2\implies 2=(x-3)^2\implies \pm\sqrt{2}=x-3&#10;\\\\\\&#10;\pm\sqrt{2}+3=x\qquad therefore\qquad (\pm\sqrt{2}+3~~~~,~~~~0)
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