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Mkey [24]
2 years ago
15

Using the following image, solve the problems below given that M is the midpoint of VW.

Mathematics
1 answer:
blsea [12.9K]2 years ago
5 0

The midpoint of a line segment divides the line segment into equal halves.

  • The value of x is 4
  • The value of VM and MW is 15
  • The value of VW is 30

Point M is the midpoint of line segment VW.

So, we have:

VM = MW

Substitute known values

4x - 1= 3x+3

Collect like terms

4x - 3x = 1 + 3

Evaluate like terms

x = 4

Hence, the value of x is 4

The expression for VM is:

VM = 4x - 1

So, we have:

VM = 4(4) - 1

VM = 15

Hence, the value of VM and MW is 15

The length of VW is the sum of both lengths.

So, we have:

VW = 15 + 15

VW = 30

Hence, the value of VW is 30

Read more about midpoints at

brainly.com/question/18315903

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An equation is shown below:
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Answer: x = 1

Step-by-step explanation:

5 ( 2x - 8 ) + 15 = -15 (write the equation)

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Select one of the factors of x2y3 − 11x2y + 6y2 − 66
EleoNora [17]
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4 years ago
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Plz help me with this math and also explain
jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

  • SI = $250
  • Rate (R) = 12\sf \dfrac{1}{2} %
  • Time (t) = 4 years

\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\

\longrightarrow \tt { 250 \times 100 = P \times 50} \\

\longrightarrow \tt { 25000 = P \times 50} \\

\longrightarrow \tt { \dfrac{25000}{50} = P } \\

\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

  • 2/7 of the balls are red.
  • 3/5 of the balls are blue.
  • Rest are yellow.
  • Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\

\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\

\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\

\longrightarrow \tt{ 31x + 1260= 35x} \\

\longrightarrow \tt{ 1260= 35x-31x} \\

\longrightarrow \tt{ 1260= 4x} \\

\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\

\longrightarrow \underline{\boxed{  \tt { 315 = x }}} \\

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\

\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\

\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\

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Answer:

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Step-by-step explanation:

Step 1: Write out inequality

-2a - 5 > 3

Step 2: Add 5 to both sides

-2a > 8

Step 3: Divide both sides by -2

a < -4

Here, we can see that any value of <em>a </em>less than -4 works. So <em>a</em> could be -124 or -5, or even -1271293587923857 and it would work.

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