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IrinaK [193]
2 years ago
15

After mitosis and cytokinesis are complete which of the following are true.

SAT
1 answer:
amid [387]2 years ago
4 0

Two new cells are formed at the end of the process of division of the cytoplasm (cytokinesis) or division of the cell nucleus (mitosis).

At the end of mitosis, the cell has two identical nuclei located at opposite cell ends, immediately the cytokinesis process is triggered, that is, the separation of both daughter cells.

  • In the entire process of cell division and cytokinesis, chromosomes condense, line up on the equatorial plate, and migrate toward the poles simultaneously.

  • When migration ends, the barriers that separate the new nuclei and the new cells are formed.

Therefore, we can conclude that the reorganization between the generated daughter nuclei produces a fractionation of the cytoplasm and definitively separates the new cells.

Learn more about mitosis and cytokinesis here: brainly.com/question/107513

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A chemist will use a sample of 30 g of ethanol (ch3ch2oh) in an experiment. in one to two sentences, make and justify a claim ab
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The number of mole of ethanol, CH₃CH₂OH the chemist will use in the experiment is 0.65 mole

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mole of CH₃CH₂OH</h3>

From the question given above, the following data were obtained:

  • Mass of CH₃CH₂OH = 30 g
  • Molar mass of CH₃CH₂OH = 12 + (1×3) + 12 + (1×2) + 16 + 1 = 46 g/mol
  • Mole of CH₃CH₂OH =?

Mole = mass / molar mass

Mole of CH₃CH₂OH = 30 / 46

Mole of CH₃CH₂OH = 0.65 mole

Learn more about mole:

brainly.com/question/13314627

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X has travelled 4 times as far as Y

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Because x=1/2at²(get rid of the first portion of x=vt+1/2at² because initial v is 0 which multiplies to 0). If the acceleration is set to for example 10 (keep this constant for both X and Y) and we use t=1 and t=2 for time (as the time travelled of X is twice that of Y). Plugging this into the equation, at t=1, x=4. At t=2, x=20. 20 is four times greater than 5, so X has travelled 4 times as far as Y.

To find the difference in speed between the two objects, use the equation v_{f}=v_{0} +at. Since the initial velocity is 0, that part can just be removed from the equation. With v=at, it is easy to see that if the time plugged in is twice for one than the other (and the acceleration is the same for both), the final result will be twice of the other as well. For example: If the acceleration is 10 again for both, then v=10t. If t is 1, the velocity is 10. If t is 2, the velocity is 20.

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