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1 year ago

After mitosis and cytokinesis are complete which of the following are true.

1 answer:

4 0

Two new cells are formed at the end of the process of division of the cytoplasm (cytokinesis) or division of the cell nucleus (mitosis).

At the end of mitosis, the cell has two identical nuclei located at opposite cell ends, immediately the cytokinesis process is triggered, that is, the separation of both daughter cells.

In the entire process of cell division and cytokinesis, chromosomes condense, line up on the equatorial plate, and migrate toward the poles simultaneously.

When migration ends, the barriers that separate the new nuclei and the new cells are formed.

Therefore, we can conclude that the reorganization between the generated daughter nuclei produces a fractionation of the cytoplasm and definitively separates the new cells.

Learn more about mitosis and cytokinesis here: brainly.com/question/107513

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How does lifelong learning help most people?

aliya0001 [1]

Lifelong learning can enhance our understanding of the world around us, provide us with more and better opportunities and improve our quality of life.

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2 years ago

Read 2 more answers

Which word best describes the tone of this excerpt? deceitful sentimental methodical respectful

svp [43]

The word that best describes the tone of the excerpt is : ( C ) Methodical

<h3>What is methodical procedure ?</h3>

Methodical procedure describes the sequential procedure in which a system of actions is been followed usually computer systems or other forms as seen in the excerpt.

Hence we can conclude that the word that best describes the tone of the excerpt is methodical.

Learn more about methodical procedure : brainly.com/question/6947486

#SPJ1

<u>Attached below is the missing excerpt </u>

<em>I knew I could never let Mom hear the messages, because protecting her is one of my most important raisons d’être, so what I did was I took Dad’s emergency money from on top of his dresser, and I went to the Radio Shack on Amsterdam. It was on a TV there that I saw that the first building had fallen. I bought the exact same phone and ran home and recorded our greeting from the first phone onto it. I wrapped up the old phone in the scarf that Grandma was never able to finish because of my privacy, and I put that in a grocery bag, and I put that in a box, and I put that in another box, and I put that under a bunch of stuff in my closet, like my jewelry workbench and albums of foreign currencies. </em>

6 0

1 year ago

the height of a bottle rocket, in meters, is given by the function s(t)=−9t2+103t+403. find the average velocity of the bottle r

zaharov [31]

The average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

The given parameters;

s(t) = -9t² + 103t + 403
time interval (4.499, 4.5), and (4.5, 4.501)

The average velocity of the bottle rocket over the intervals is calculated as follows;

when the interval = [<em>4.499, 4.5</em>]

$s(4.499)= -9(4.499)^2 + 103(4.499) + 403 = 684.22 \ m\\\\s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m$

$v = \frac{\Delta \ s}{\Delta \ t} = \frac{684.25 - 684.22}{4.5 - 4.499} = 30 \ m/s$

when the interval = [<em>4.5, 4.501</em>]

$s(4.5) = -9(4.5)^2 + 103(4.5) + 403 = 684.25 \ m\\\\s(4.501) = -9(4.501)^2 + 103(4.501) + 403 =684.27 \ m\\\\v= \frac{684.27 - 684.25}{4.501-4.5} \\\\v = 20 \ m/s$

The instantaneous velocity of the bottle rocket at time t=4.5;

$v = \frac{d \ s(t)}{dt} = -18t + 103\\\\v(4.5) = -18(4.5) + 103\\\\v(4.5) = 22 \ m/s$

Thus, the average velocity of the bottle rocket are two given time intervals is 30 m/s and 20 m/s respectively, while the instantaneous velocity at 4.5 seconds is 22 m/s.

Learn more here: brainly.com/question/25009886

7 0

1 year ago

The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}

AlladinOne [14]

Recall that √x has a domain of x ≥ 0.

So, f(x) is defined as long as

(x + 1)/(x - 1) ≥ 0

• We have equality when x = -1

• Otherwise (x + 1)/(x - 1) is positive if both x + 1 and x - 1 are positive, or both are negative:

$\begin{cases}x+1>0 \implies x>-1 \\ x-1>0 \implies x>1\end{cases} \implies x > 1$