10 images per day. Since it can receive 3 mb per second for 11 hours a day, that’s up to 118,800 megabits it can receive in one day. By multiplying the amount of gigabits in a typical picture (11.2) by the amount of megabits in a gigabit (1024) you get that there’s 11,468.8 megabits in each picture. Lastly, divide the number of megs that the station receives in one day by the amount of megs in a picture, and you get 10 and some change, therefore it can receive up to ten FULL pictures in a day
Answer:
3
Explanation:
(1/3x-1/6y)×18=4×18 ⇒ 6x-3y=72
6x-ay=8 if a=3 ⇒ 6x-3y=8
72≠8
a=3 ⇒ system has no solution
Answer:there is a vgraph so where it says 4 at the bottom then go under to -2 then ur done.
Explanation:
Answer:
PART A
- Red: 7/29
- Blue: 8/29
- Yellow: 5/29
- Green: 9/29
PART B
- Red or blue: 7/29 + 8/29 = 15/29
- Yellow or green: 5/29 + 9/29 = 14/29
- Blue or yellow or green: 8/29 + 5/29 + 9/29 = 22/29
Explanation:
In this case where the question is asking or <u>OR</u> and the events are <u>mutually exclusive</u> (Mutually exclusive meaning you can't attain two or three different colors in one pick), the compound probability is the sum of the probability of each component event (Probability of Red <u>OR</u> Blue = P(Red) + P(Blue) = 7/29 + 8/29 = 15/29)
Answer:
100N
Explanation:
m= 5kg
a= 20 m/s^2
F= ma = 5kg x 20 m/s^2 = 100kg m/s^2 = 100N
