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Arada [10]
3 years ago
14

Find the unit rate. 64 ounces in 4 cans

Mathematics
2 answers:
Marysya12 [62]3 years ago
8 0

The unit rate is 0.16 ounces per can.

Klio2033 [76]3 years ago
4 0

Answer:

16 ounces per can

Step-by-step explanation:

64/4 oz = 4/4 cans

16 oz = 1 can

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Please answer. I will mark Brainliest
den301095 [7]
Statement: 1) Triangle ABC
2) 2x 3)x=52

Reason: I’m not sure but probably addition
4 0
3 years ago
Make x the subject of y=alog(5x)
Bond [772]

Answer:

x = 0.2(10^y/a).

Step-by-step explanation:

y = alog(5x)

y = log(5x)^a)   By the definition of a log:

(5x)^a  = 10^y

5x = (10^y) ^ 1/a

x = 0.2(10^y/a)

4 0
3 years ago
Number 7 and 8 plz answer quickly
Flauer [41]

(7) m∠A = 52°

(8) m∠B = 117°

Solution:

(7) Let us first define the supplementary and complementary angles.

Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°

Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°

Given supplement of 142° = 180° – 142°

                                           = 38°

Complement of ∠A = Supplement of 142°

⇒ Complement of ∠A = 38°

Measure of ∠A = 90° – 38°

                          = 52°

Hence m∠A = 52°.

(8) Given complement of 27° = 90° – 27°

                                                 = 63°

Supplement of ∠B = Complement of 27°

⇒ Supplement of ∠B = 63°

Measure of ∠B = 180° – 63°

                          = 117°

Hence m∠B = 117°.

3 0
3 years ago
Suppose the local Barons team wins every game they play with a probability of 0.75. What is the probability that the Barons woul
kondaur [170]

Answer:

The probability is 0.173

Step-by-step explanation:

The probability is of winning is 0.75 = 75/100 = 3/4

This means that the probability of losing is 0.25 = 25/100 = 1/4

So if they are two win 4 games, they will lose three

We can get this probability using the Bernoulli approximation of the binomial theorem

So here, we have

P(X = 4) = 7 C 4 * 0.75^4 * 0.25^3

= 0.173034667969

which is approximately 0.1730

6 0
2 years ago
Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11
a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that  cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

hyp^{2} = adj^{2}  + opp ^{2}  \\opp = \sqrt{hyp^{2} - adj^{2}  } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ\neq 1/cosθ but cscθ = 1/sinθ

6 0
3 years ago
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