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Kobotan [32]
2 years ago
15

What can you multiply by to find: 50% of a number? 10% of a number? 75% of a number?

Mathematics
1 answer:
adelina 88 [10]2 years ago
5 0

Answer:

50% is 0.5

10% is 0.1

75% is 0.75

Step-by-step explanation:

When multiplying to find the percent of a number, you make it a decimal by dividing it by 100.

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Cellular phone service is available for $35 per month for 1118 minutes. What is the monthly cost per minute? Round your answer t
olga nikolaevna [1]

Answer:

Step-by-step explanation:

a=bxh

7 0
3 years ago
Mike drove 10 miles in 30 minutes, what's the average speed in miles per hour
ollegr [7]
Mike is driving 20 miles per hour

If he is driving 10 miles in 30 mins
(1/2 an hour) if you times both by two it tells you the MPH that Mike is driving.
7 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
1,272 divided by 21?
Ann [662]

Answer:

106

Step-by-step explanation:

1272/21

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%284x3%20%2B%202x%291" id="TexFormula1" title="y = (4x3 + 2x)1" alt="y = (4x3 + 2x)1
Amanda [17]
I think it’s dy/dx=2
4 0
3 years ago
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