Answer:
The vertex is (-19,-14)
Step-by-step explanation:
y = 3(x+19)^2 - 14
The equation is written in vertex form
y = a(x-h)^2 + k where (h,k) is the vertex
y = 3(x- -19)^2 - 14
The vertex is (-19,-14)
Answer:
-y+(x-12)=-1
Step-by-step explanation:
Answer:189
Step-by-step explanation:
Answer:
Step-by-step explanation:
Unless we set x^2 + 8x + 15 equal to zero, we don't have an equation to be solved. I will assume that the problem is actually x^2 + 8x + 15 = 0.
The coefficients of this quadratic are {1, 8, 15}, and so the "discriminant" b^2 - 4ac is (8)^2 - 4(1)(15), or 4. Because the discriminant is positive, we know that there are two real, unequal roots.
Continuing with the quadratic formula and knowing that the discriminant is 4, we get:
-8 ± √4 -8 ± 2
x = ---------------- = --------------- , or x = -2 ± 1: x = -3 and x = -5
2 2
