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4 years ago

(x^2-4x)^2+7x^2-28x+12=0

Mathematics

1 answer:

Valentin [98]4 years ago

7 0

Answer:

$x^4-9x^2-28x=-12$

Step-by-step explanation:

$(x^2-4x)^2+7x^2-28x+12=0$

$(x^4-16x^2)+7x^2-28x=-12$

$x^4-9x^2-28x=-12$

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Answer:

6/25

Step-by-step explanation:

P(have belief) =76/100 = 19/25

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Answer: vector equation r = (7+3t)i + (4+2t)j + (5 - 5t)k

parametric equations: x = 7 + 3t; y = 4 + 2t; z = 5 - 5t

Step-by-step explanation: The vector equation is a line of the form:

r = $r_{0}$ + t.v

where

$r_{0}$ is the position vector;

v is the vector;

For point (7,4,5):

$r_{0}$ = 7i + 4j + 5k

Then, the equation is:

r = 7i + 4j + 5k + t(3i + 2j - k)

r = (7 + 3t)i + (4 + 2t)j + (5 - 5t)k

The parametric equations of the line are of the form:

x = $x_{0}$ + at

y = $y_{0}$ + bt

z = $z_{0}$ + ct

So, the parametric equations are:

x = 7 + 3t

y = 4 + 2t

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3 years ago

When I was 6 years old, my sister was half of my age and my brother was twice of my age. 5 years later, what is the sum of the s

enot [183]

The Sum of all the siblings ages are 36.

Explanation:

Your sister was half your age(3).

Your brother was twice your age(12).

It says 5 years later...

so then your sister is 8

brother is 17

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When you add all of these ages up you get the answer 36.

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Step-by-step explanation:

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