3 years ago

(x^2-4x)^2+7x^2-28x+12=0

Mathematics

1 answer:

Valentin [98]3 years ago

7 0

Answer:

$x^4-9x^2-28x=-12$

Step-by-step explanation:

$(x^2-4x)^2+7x^2-28x+12=0$

$(x^4-16x^2)+7x^2-28x=-12$

$x^4-9x^2-28x=-12$

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