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3 years ago

Substitute the value in for the variable. Then solve. Remember your order of operations!

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

4 0

Answer:

208

Step-by-step explanation:

4(50+2)=4*52=208

*When N=2 where ever you see an N you put a 2* also perenthsies come before multipilicaion so you do that first.

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rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4

OleMash [197]

Answer:

The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of y⁴ is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.

The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial

now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

Conclusion:-

The degree of given polynomial is '5'

The co-efficient of y⁴ is '-17'

5 0

4 years ago

I need help with this problem please

NNADVOKAT [17]

n must be 0, since x ⁿ = 1 for all positive, real x if n = 0. So the answer is A.

7 0

3 years ago

What is the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81?

Marizza181 [45]

Answer: d. 1.3333

Step-by-step explanation:

We know that the standard error of a sampling distribution is given by :-

$S.E.=\dfrac{\sigma}{\sqrt{n}}$

, where $\sigma$ = Population standard deviation.

n= Sample size.

AS per given , we have

$\sigma =12$

n=81

Then, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 will be :-

$S.E.=\dfrac{12}{\sqrt{81}}$

$=\dfrac{12}{\sqrt{9^2}}=\dfrac{12}{9}\\\\=\dfrac{4}{3}\\\\\approx1.3333$

Hence, the standard error of a sampling distribution with a population standard deviation of 12 and the sample size of 81 is 1.3333.

Thus the correct answer is d. 1.3333 .

6 0

3 years ago

An exam consists of 10 true-or-false questions. If a student guesses at every answer, what is the probability that he or she wil

zysi [14]

This can be solved by using the binomial distribution. The probability of guessing correctly is 0.5, and the probability of making a wrong guess is also 0.5.
$P(6\ correct)=10C6\times(\frac{1}{2})^{6}\times(\frac{1}{2})^{4}=\frac{210}{1024}=0.205$

5 0

3 years ago

Which set of coordinates doesn’t represent the problem?

Semmy [17]

ThE answer is C, congrats

5 0

3 years ago