The result of a subtraction problem is called a quotient

Simplify the expression. Write your answer as a power.<br><br> 8^10⋅8^4

topjm [15]

8^14 is the answer.

This is because since they both have the same base, the exponents could be added together if the numbers are multiplied together

3 0

3 years ago

Read 2 more answers

Circle A has center (0, 0) and radius 3. Circle B has center (-5, 0) and radius 1. What sequence of transformations could be use

Dmitrij [34]

A translation of T(x, y) = (- 5, 2) and a dilation with center (- 5, 2) with a scale factor of 1 / 3 are necessary to transform circle A into circle B. (Correct choice: D)

<h3>What sequence of rigid transformations can be done on a circle</h3>

In this problem we must determine the sequence of transformations require to transform circle A into circle B. From analytical geometry we know that the equation of the circle in standard form is:

(x - h)² + (y - k)² = r²

Where:

(h, k) - Coordinates of the center.
r - Radius of the circle.

Then, we need to apply the following rigid transformations:

Translation

f(x, y) → f(x - h, y - k), where (h, k) is the translation vector.

Dilation with center at the center of the circle

r → k · r, where k is the scale factor.

The circle A is represented by x² + y² = 3, then we derive the expression for the circle B:

f(x, y) → f(x + 5, y - 2)

(x + 5)² + (y - 2)² = 9

r → k · r

(x + 5)² + (y - 2)² = (1 / 3)² · 9

(x + 5)² + (y - 2)² = 1

Then, a translation of T(x, y) = (- 5, 2) and a dilation with center (- 5, 2) are necessary to transform circle A into circle B.

To learn more on rigid transformations: brainly.com/question/28004150

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8 0

1 year ago

HELP! WILL NAME BRAINEST!!!!

Irina18 [472]

the best answer is b

5 0

3 years ago

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Un apostador pierde en su primer juego el 30% de su dinero, en el segundo juego pierde el 50% de lo que perdió; finalmente en el

sergiy2304 [10]

Responder:

26,62

Explicación paso a paso:

Sea x el dinero original que tenía el jugador:

si un jugador pierde en su primer juego el 30% de su dinero, la cantidad perdida será;

$= 30/100 \ of \ x\\= 0.3x$

Si en el segundo juego pierde el 50% de lo que perdió, entonces la cantidad perdida en el segundo juego será:

$= 50/100 \ of \ 0.3x\\= 0.5 \times 0.3x\\= 0.15x$

Si en el tercer juego pierde el 40% de todo lo que ha perdido, la cantidad perdida en el tercer juego será:

$=\frac{40}{100} \ of \ (0.3x+0.15x) \\= 0.4(0.45x)\\= 0.2025x$

Si la cantidad que le queda para seguir apostando es de 37 soles, entonces para calcular la cantidad original que tiene, sumaremos toda la cantidad perdida y la cantidad restante y equipararemos la cantidad original x como se muestra:

0,3x + 0,15x + 0,2025x + 37 = x

0,6525x + 37 = x

x-0,6525x = 37

0,3475x = 37

x = 37 / 0,3475

x = 106,48

La cantidad que tenía originalmente era de 106,48

75% de 106,48

= 75/100 * 106,48

= 0,75 * 106,48

= 79,86

Tomando la diferencia entre su monto original y su 75% será:

$= 106.48-79.86\\= 26.62$

3 0

3 years ago

Find the values of x and y if 5 ˣ⁻³ x 3²ʸ⁻⁸ =225

-BARSIC- [3]

Answer:

x = 5, y = 5

Step-by-step explanation:

${5}^{x - 3} \times {3}^{2y - 8} = 225 \\ {5}^{x - 3} \times {3}^{2y - 8} = 25 \times 9 \\ {5}^{x - 3} \times {3}^{2y - 8} = {5}^{2} \times {3}^{2} \\ equating \: like \: power \: terms \: from \: both \:\\ sides \\ {5}^{x - 3} = {5}^{2} \\ x - 3 = 2 (Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ x = 3 + 2 \\ \huge \red{ \boxed{ x = 5}} \\ \\ {3}^{2y - 8} = {3}^{2} \\ 2y - 8 = 2(Bases\: are\: equal, \: so\: exponents \: \\will\: also\: be\: equal) \\ 2y = 2 + 8 \\ 2y = 10 \\ y = \frac{10}{2} \\ \huge \purple{ \boxed{y = 5}}$

5 0

3 years ago