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Nookie1986 [14]
2 years ago
6

Determine the equation of a line parallel to the graph of y=3x - 9 and goes through the point (2, 10)​

Mathematics
1 answer:
hjlf2 years ago
6 0

Answer:

y=3x+4

Step-by-step explanation:

since the line is parallel it has the same slope so we have y = 3x + b. plug in the point (2,10) to get 10 = 3*2 + b, so b=4. so the equation is y = 3x +4

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Axis of symmetry: x=4; points: (3,-2), (6,-26); opening downward
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Vertex form is
y=a(x-h)^2+k
vertex is (h,k)
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y=a(x-4)^2+k

we have some points
(3,-2) and (6,-26)
input and solve for a and k

(3,-2)
-2=a(3-4)^2+k
-2=a(-1)^2+k
-2=a(1)+k
-2=a+k

(6,-26)
-26=a(6-4)^2+k
-26=a(2)^2+k
-26=a(4)+k
-26=4a+k

we have

-2=a+k
-26=4a+k
multiply first equation by -1 and add to second

2=-a-k
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-24=3a+0k

-24=3a
divide both sides by 3
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-2=a+k
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the equation is
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3 years ago
Solve the inequality 13 &gt; 3x + 1
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step by step explanation:

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Answer:

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Step-by-step explanation:

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