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Nookie1986 [14]
2 years ago
6

Determine the equation of a line parallel to the graph of y=3x - 9 and goes through the point (2, 10)​

Mathematics
1 answer:
hjlf2 years ago
6 0

Answer:

y=3x+4

Step-by-step explanation:

since the line is parallel it has the same slope so we have y = 3x + b. plug in the point (2,10) to get 10 = 3*2 + b, so b=4. so the equation is y = 3x +4

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mars1129 [50]
The answer to your question is 11.25
4 0
3 years ago
Which shows the phrase "the product of a number and 3" as a variable expression?
JulijaS [17]

The algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z

<h3>How to write an algebraic expression for the word phrase "the product of a number and 3" as a variable expression?</h3>

The word phrase is given as:

"the product of a number and 3"

Represent the number with z

So, the word phrase can be rewritten as:

"the product of a number z and 3"

The product of a number z and 3 is represented as:

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When evaluated,, the expression becomes

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Hence, the algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z

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3 0
1 year ago
Find the y-intercept for the line represented by this equation -2y=4x+8
ad-work [718]
The y intercept = -4

Also, the slope of the line (if needed) is -2.



6 0
3 years ago
Read 2 more answers
When Maggie hooks her dog up to a rope that is staked in the yard, the dog can walk a distance of about 76 feet along the circum
pentagon [3]

Answer:

12.1

Step-by-step explanation:

76/2π

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3 0
3 years ago
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Pleaseeeee helpppppp!!
Sergio [31]

Answer:  The equation of the circle as specified is (x+5)² + (y -1)² = 25

Step-by-step explanation:  Use the Pythagorean Theorem to calculate the length of the radius from the coordinates given for the triangle location: A(-1,4), B(-1,1) and C(-5,1)  

subtract y-values of A & B 4-1=3 AB = 3

subtract x-values of B &C -5-(-1) =4 BC=4  3² + 4² = 9 + 16 = 25  

√25 = 5   AC = 5  That is the radiuus of the circle.    

The sides of the triangle are AB=3, BC=4, AC=5.

Use the equation for a circle:

( x - h )² + ( y - k )² = r², where ( h, k ) is the center and r is the radius.

Use the coordinates of C, (-5, 1) as h and k in the equation

Substituting those values, we have (x -[-5])² + (y -[1])² = 5²

Simplify:  (x+5)² + (y -1)² = 25

A graph of the circle is attached. The radius is AC, between the center C (-5,1) and A( -1,4) on the circumference.  (Sorry, I still need to learn how to create line segments!)

8 0
3 years ago
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