Answer:
Step-by-step explanation:
(4,6) and (20,14) are points on the line.
slope of line = (14-6)/(20-4) = 8/16= 1/2
point-slope equation for line of slope 1/2 that passes through (6,4):
y-4 = (½)(x-6)
in slope-intercept form:
y = ½x + 1
y-intercept = 1
y = mx + b
m = slope and b = y-intercept
We can arrange 6y = x - 12 in the form of y = mx + b
6y = x - 12
y = 1/6(x) - 2
Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.
Negative reciprocal of 1/6 is -6.
The equation for the perpendicular line is
y = -6x + b
To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates
-4 = -6(4) + b
b = -4 + 6(4)
b = -4 + 24
b = 20
So the equation for the perpendicular line is y = -6x + 20
Answer:nothin much
Step-by-step explanation:
Answer:
The LCM of 10, 12, and 18 is 180.
HOPE THIS HELPED!!!!!!!!!!!!XDDDDDDDD
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