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3 years ago

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Mathematics

1 answer:

Lana71 [14]3 years ago

6 0

In a triangle when an angle between two equal length sides is 60 that means that the triangle is equilateral.

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Rewrite using a single positive exponent..- 7^2 —— 7^-4

stellarik [79]

Answer:

7 ^2 ⋅ 7 ^4 = 49^6

Step-by-step explanation:

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2 years ago

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What is an equation of the line that is perpendicular to y=−3/4x+6 and passes through the point (3, 9) ?

irga5000 [103]

Two straight lines perpendicular to each other, the slope of which is negative reciprocal.

y=-4/3x+b

The known points are put into the linear equation

y=-4+b

b=13

y=-4/3x+13

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3 years ago

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Find x. 8 2radius3 8 8radius3 (hurry plz, will give brainliest) -15pts-

-BARSIC- [3]

Answer:

Answere is X= 8

Step-by-step explanation:

Use sine law

Sin(angle) = Opposite/ Hypotenuse

Sin (30) = 4 /X

X = 4 / sin (30)

X = 8

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3 years ago

Factorise -3c(d-2e)-d(d-2e)

nlexa [21]

-3c(d-2e) -d(d-2e)
(-3c-d)(d-2e)
-1(3c+d)(d-2e)

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2 years ago

A researcher wants to determine whether there is a relationship between age and the number of text messages sent in a given day.

Hatshy [7]

Answer:

$ME= 2.58 \sqrt{\frac{0.8(1-0.8)}{125} +\frac{0.625 (1-0.625)}{120}}= 0.1465$

The best option would be:

d. 0.1465

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for brand 18-25 users

$\hat p_A =\frac{100}{125}=0.8$ represent the estimated proportion for 18-25 users

$n_A=125$ is the sample size

$p_B$ represent the real population proportion for 26-35 users

$\hat p_B =\frac{75}{120}=0.625$ represent the estimated proportion for 26-35 users

$n_B=120$ is the sample size required for Brand B

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And the margin of error is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

And if we replace we got:

$ME= 2.58 \sqrt{\frac{0.8(1-0.8)}{125} +\frac{0.625 (1-0.625)}{120}}= 0.1465$

The best option would be:

d. 0.1465

8 0

3 years ago