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UNO [17]
3 years ago
7

What are the four functions that are increasing on the interval

Mathematics
2 answers:
mina [271]3 years ago
6 0

Answer:

Tbh i don’t really know

Step-by-step explanation:

Ask someone else

Furkat [3]3 years ago
5 0
Identity function
Cubing function
Reciprocal function
Sine function
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Suppose a population grows according to the logistic equation but is subject to a constant total harvest rate of H. If N(t) is t
Elenna [48]

Answer:

a) Equilibrium point : [ 947, 53 ]

b) N = 947 is stable equilibrium, N = 53  is unstable equilibrium

c) N0, the population will not go extinct

Step-by-step explanation:

a)

Given that;

r = 2, k = 1000, H = 100

dN/dT = R(1 - N/k)N - H

so we substitute

dN/dt = 2( 1 - N/1000)N - 100

now for equilibrium solution, dN/dt = 0

so

2( 1 - N/1000)N - 100 = 0

((1000 - N)/1000)N = 50

N^2 - 1000N + 50000 = 0

N = 1000 ± √(-1000)² - 4(1)(50000)) / 2(1)

N = 947.213 OR 52.786

approximately

N = 947 OR 53

Therefore Equilibrium point : [ 947, 53 ]

b)

g(N) = 2( 1 - N/1000)N - 100

= 2N - N²/500 - 100

g'(N) = 2 - N/250

SO AT 947

g'(N) = g'(947) =  2 - 947/250 = -1.788 which is less than (<) 0

so N = 947 is stable equilibrium

now AT 53

g'(N) = g"(53) = 2 - 53/250 = 1.788 which is greater than (>) 0

so N = 53  is unstable equilibrium

The capacity k=1000

If the population is less than 53 then the population will become extinct but since the capacity is equal to 1000 then the population will not go extinct.

6 0
3 years ago
Can some one please help me?
n200080 [17]

Answer: C

Step-by-step explanation: basicly all u have to do juss multilpy how many on top with the extra boxes, hope this helpss :)

3 0
3 years ago
Read 2 more answers
Given g(x) = 3x + 3, find g(-6).
Strike441 [17]

Answer:

-15

Step-by-step explanation:

g(x) = 3x + 3

Let x = -6

g(-6) = 3*-6 + 3

           = -18 +3

            = -15

6 0
3 years ago
Round 1.07 to the tenths place.
galben [10]
Answer: 1.10
Work: 5 or more raise the next digit, 4 or less keep it
5 0
3 years ago
Water fills a tank at a rate of 150 litres during the first hour, 350 litres during the second, 550 litres during the third and
Alborosie
Putting this as an arithmetic sequence gives:

u_n = 150+200(n-1)

The sum of the series = 16 x 7 x 7 = 784 m^3 = 784 000 L

The sum of an arithmetic series can be written as:

S_n=n/2 [2a+(n-1)d] = 784 000&#10;\\n/2[2(150)+(n-1)200] = 784 000&#10;\\n[300+200(n-1)=1 568 000&#10;\\300n+200n^2-200n = 1 568 000&#10;\\200n^2+100n- 1 568 000 = 0&#10;\\2n^2 +n- 15680 = 0&#10;&#10;\\n= 88.2...,-88.7

n has to be positive, so we get

n = <u>88.2 hours (3 s.f.)</u>
3 0
3 years ago
Read 2 more answers
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