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amid [387]
3 years ago
11

Let x be the speed of Aro’s paddling and let y be the speed of the river.

Mathematics
2 answers:
grigory [225]3 years ago
7 0

Answer:

Aro can paddle at a speed of 1.56 miles per hour.

The river’s speed is 0.52 miles per hour.

Step-by-step explanation:

trust

Olenka [21]3 years ago
6 0

Answer:

1.56

0.52

Step-by-step explanation:

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Anyone have these or know them???
horsena [70]

The answer would be y = 6x.

The reason for this is that when we add a number in front of x, it makes it go up vertically by the factor of that number. So if we are to stretch the graph vertically, the only way we can do it is by making 6 the coefficient.

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What is the answer to this
son4ous [18]
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6 0
3 years ago
Solve for X and show work
Len [333]
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7 0
3 years ago
If the sum of the even integers between 1 and k, inclusive, is equal to 2k, what is the value of k?
Alisiya [41]
If k is odd, then

\displaystyle\sum_{n=1}^{\lfloor k/2\rfloor}2n=2\dfrac{\left\lfloor\frac k2\right\rfloor\left(\left\lfloor\frac k2\right\rfloor+1\right)}2=\left\lfloor\dfrac k2\right\rfloor^2+\left\lfloor\dfrac k2\right\rfloor

while if k is even, then the sum would be

\displaystyle\sum_{n=1}^{k/2}2n=2\dfrac{\frac k2\left(\frac k2+1\right)}2=\dfrac{k^2+2k}4

The latter case is easier to solve:

\dfrac{k^2+2k}4=2k\implies k^2-6k=k(k-6)=0

which means k=6.

In the odd case, instead of considering the above equation we can consider the partial sums. If k is odd, then the sum of the even integers between 1 and k would be

S=2+4+6+\cdots+(k-5)+(k-3)+(k-1)

Now consider the partial sum up to the second-to-last term,

S^*=2+4+6+\cdots+(k-5)+(k-3)

Subtracting this from the previous partial sum, we have

S-S^*=k-1

We're given that the sums must add to 2k, which means

S=2k
S^*=2(k-2)

But taking the differences now yields

S-S^*=2k-2(k-2)=4

and there is only one k for which k-1=4; namely, k=5. However, the sum of the even integers between 1 and 5 is 2+4=6, whereas 2k=10\neq6. So there are no solutions to this over the odd integers.
5 0
3 years ago
A map shows the distance between the corner of Cactus Road and 1st Street and the corner of 1st Street and Merle Road as 3 inche
oksano4ka [1.4K]
C: 11.1 mi Just do 3.7*3 to get the answer which is from the scale 1:3.7.
6 0
3 years ago
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