In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.

If you can not understand the below symbols see the attachment below

f  f ()

Where: f = Shear Stress on Failure Plane

´= Normal Stress on Failure Plane

See the graph in the attachment

For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula: shear stress =  f  c   tan 

Where,

• f is Shear Stress on Failure Plane

• c is Cohesion

•  is Normal Total Stress on Failure Plane

•  is Friction Angle

8 0

3 years ago

In which area of the screen can features and functions of Word be accessed?

abruzzese [7]

Answer:

Toolbar

Explanation:

j don't know if you meant that instead of scroll bar, but tool bar is the answer

5 0

3 years ago

Underinflated tires flex too much and build up heat, which can lead to tire blowouts.

ziro4ka [17]

Driving on under-inflated tires is very dangerous. If tires pressure is too low, too much of the tire's surface area touches the road, which increases friction. The more friction you have, the more heat is applied to the tires. Then, too much heat will make them overheat which can cause tread separation and, yes, blowouts. Therefore, the answer is true.

5 0

3 years ago