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Vitek1552 [10]
3 years ago
13

Your ghost hunting group is recording the sound inside a haunted Stanford classroom for 20 hours as MP3 audio files. About how m

uch data will that be, expressed in GB
Computers and Technology
1 answer:
Mademuasel [1]3 years ago
3 0

Answer:

1.152 GB if it will be at 128 kbps quality

Explanation:

So, let's say you choose your mp3 be 128 kbps (kilobits per second).

One byte is 8 bits. So 128 kbps = 16 kilobytes per second.

There is 60*60 seconds in one hour. So 16*60*60 = 57.6 megabytes per hour

Multiply by 20 hours to get your answer: 57.6*20 = 1152 MB = 1.152 GB.

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What does the hot end of a 3D printer do?
Alex Ar [27]

Answer:

The hot end is where the heated filament comes out and moves across the print bed to create your 3D object! ... Different materials may print best at different temperatures so the sensor is important and it's temperature can be set with your slicing program.

Explanation:

7 0
3 years ago
g Write a user-defined MATLAB function for the following math function: y ( x )=(−.2 x 3 +7 x 2 )e −.3x The input to the functio
kolezko [41]

Answer:

Go to explaination for the step by step answer.

Explanation:

a)Code

function[y]=operation(x) % this function takes x as input and returns y as output

y=(-0.2*x^3+7*x^2)*exp(-0.3*x)

end

% call this function in command widow by typing operation(value of x) like shown in figure in the first attachment.

b. write a code of above function in one script window and save the code with same name as name of function that is name of script should be saved as operation.Now copy paste the below code in new script window and run the code

clc

clear all

x=-2:.1:6

n=length(x)

for i=1:1:n

a=x(i)

y(i)=operation(a)

end

plot(y,x)

xlabel('X')

ylabel('Y')

Please kindly check attachment for pictorial answers that supports the code.

4 0
3 years ago
In Florida no fault insurance is optional for owners of a vehicle
Elena-2011 [213]
It is false, Its obligatory. 
7 0
3 years ago
a) (20 points) Define the method inDogish recursively such that it returns true if the word is in dog-ish and false if it is not
tia_tia [17]

Answer:

/ Main.java

class Main {

     public static void main(String[] args) {

           //System.out.println(inDogish("aplderogad"));

           //System.out.println(inXish("aplderogad", "dog"));

     }

     // returns true if the word is in dog-ish

     // returns false if word is not in dog-ish

     public static boolean inDogish(String word) {

           /**

           * Note: we can use the inXish() method to complete this method in a

           * single line if you want. just write 'return inXish(word,"dog");' and

           * you are done.

           */

           // if word is null or empty, returning false

           if (word == null || word.length() == 0) {

                 return false;

           }

           // converting word to lower case

           word = word.toLowerCase();

           // if 'd' does not exist on the word, returning false

           if (!dogishHelper(word, 'd')) {

                 return false;

           }

           // removing the characters upto first 'd' in word

           word = word.substring(word.indexOf('d') + 1);

           // if 'o' does not exist on the word, returning false

           if (!dogishHelper(word, 'o')) {

                 return false;

           }

           // removing the characters upto first 'o' in word

           word = word.substring(word.indexOf('o') + 1);

           // if 'g' does not exist on the word, returning false, otherwise

           // returning true

           if (!dogishHelper(word, 'g')) {

                 return false;

           } else {

                 return true;

           }

     }

     // necessary to implement inDogish recursively.

     // returns true if letter is in word, else not.

     public static boolean dogishHelper(String word, char letter) {

           // if word is empty, returning -1

           if (word == null || word.length() == 0) {

                 return false;

           }

           // if first character in word is letter, returning 0

           if (word.charAt(0) == letter) {

                 return true;

           }

           return dogishHelper(word.substring(1), letter);

     }

     // the best thing about the above helper method is that we can use it in

     // inXish method also

     // a generalized version of the inDogish method

     public static boolean inXish(String word, String x) {

           // if x is empty, returning true (base case, which means all the letters

           // in x are in word in that order)

           if (x.length() == 0) {

                 return true;

           }

           // getting first character of x

           char first = x.charAt(0);

           // if first character does not exist on the word, returning false

           if (!dogishHelper(word, first)) {

                 return false;

           }

           // calling and returning inXish recursively, passing the word after

           // removing characters upto first occurrance of char first, and x after

           // removing first character from it

           return inXish(word.substring(word.indexOf(first) + 1), x.substring(1));

     }

}

Explanation:

7 0
4 years ago
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galben [10]

Answer:

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