To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
Answer:
The missing information is attached in the picture below.
The company made $292.5 dollars in profit.
Step-by-step explanation:
Using the information provided by the table, we can calculate how much money was spent
1. gravel
12 and a half cubic yards * $15 = $187.5
2. tar/sealant
$0.15 per square foot * (75*20 ft^2) = $225
3. labor
$10 per hour * 25 hours = $250
4. insurance
fixed $45
We add all the expenses together
$(187.5 + 225 + 250 + 45) = $707.5
The profit will be equal to
$1000 - $707.5 = $292.5
Step-by-step explanation:
D=W over F j3jejensbshhsnsnsnjs
<span>2cos^2x = sin2x
2cos^2x = 2sin x cos x
(2sin x cos x) / (2cos^2x) = 1
sin x / cos x = 1
tan x = 1
x = π/4</span>
Y=3 x=119292 hope this helps!
