Answer:
0.1019
Step-by-step explanation:
Probability, p=12%=0.12
Sample size, n=130 students
Those writing with left=14 students
Using the formula for binomial distribution
P(X≤x)=![\left[\begin{array}{}n\\x\end{array}\right]p^{x}(1-p)^{n-x}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7B%7Dn%5C%5Cx%5Cend%7Barray%7D%5Cright%5Dp%5E%7Bx%7D%281-p%29%5E%7Bn-x%7D)
Substituting 0.12 for p, 130 for n, 14 for x we obtain
P(X≤x)=![\left[\begin{array}{}130\\14\end{array}\right]0.12^{14}(1-0.12)^{130-14}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7B%7D130%5C%5C14%5Cend%7Barray%7D%5Cright%5D0.12%5E%7B14%7D%281-0.12%29%5E%7B130-14%7D)
P(X≤x)=
P(X≤x)=0.1019
Answer:
The percent change in salary from one job to the next is 88.57%.
Step-by-step explanation:
The previous salary of per hour = $8.75 per hour
The current salary of per hour = $16.50 per hour
Change in the salary rate per hour = Current salary - Previous Salary
= $16.50 per hour - $8.75 per hour
=$7.75 per hour
⇒The change in the salary per hour rate is $7.75
Now, 
= 
or, the change in salary percentage is 88.57%
Hence, the percent change in salary from one job to the next is 88.57%.
I hope this helps you
sec Q=1/cos Q
2=1/cos Q
cos Q= 1/2
Q=30+2.pi.n
Q=330+2.pi.n
n€Z