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3 years ago

Please help meeeeeeeeeee

Mathematics

1 answer:

Darina [25.2K]3 years ago

3 0

If you need help for all 3 questions then ok.
Here’s what you need to do. If they give you a rectangular prism with a side length of #, that number is the length, width and height. I’ll help you for the first picture. They asked how many cubic blocks with a SIDE LENGTH of 1/7 in can fill in a cube with the SIDE LENGTH of 3/7 in. Here is your equation: (3/7 x 3/7 x 3/7) / (1/7 x 1/7 x 1/7). That’s how you solve it. (The slash stands for division.) Now do the same thing with the other pictures. They will ask you how many blocks with a side length of # can fill in a prism with the length, width, and height (or just a side length without saying the l, w and h.) Hopefully this helped! If I got it wrong or if you need help cause you didn’t get what I mean, let me know.

bYe

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Answer:

The steps to do :

$- \frac{2}{5} \div \frac{6}{8}$

$= - \frac{2}{5} \times \frac{8}{6}$

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3 years ago

Which are the solutions of x2 = 19x + 1?

Finger [1]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

we have

$x^2=19x+1$

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-x^{2}-19x-1=0$

$a=1\\b=-19\\c=-1$

substitute in the formula

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

therefore

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

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