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elena55 [62]
3 years ago
12

I’ll mark the brainiest :)

Mathematics
1 answer:
Zinaida [17]3 years ago
3 0

Answer:

IGHJK you are interested please let me brainliests

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the second side of a triangular deck is 5 feet longer than the shortest side,and the third side is 5 feet shorter than twice the
MatroZZZ [7]

first (shortest) side = x

second side = x + 5

third side = 2x - 5

the perimeter = 64 ft and is equal x + (x + 5) + (2x - 5)

x + x + 5 + 2x - 5 = 64

4x = 64 |:4

x = 16 ft

x + 5 = 16 + 5 = 21 ft

2x - 5 = 2(16) - 5 = 27 ft

Answer: 16ft, 21ft and 27ft.

7 0
3 years ago
M(9, 8) is the midpoint of RS . The coordinates of S are (10, 10). What are the coordinates of R?
Kipish [7]

Answer:

D) (8, 6)

Step-by-step explanation:

Given: M(9, 8) is the midpoint of RS . The coordinates of S are (10, 10).

Here we have to use the mid-point formula:

x = \frac{x_1 + x_2}{2}  ; y = \frac{y_1 + y_2}{2}

Here (x, y) is the midpoint.

(x, y) = M(9, 8)

(x2, y2) = (10, 10)

Here x = 9, y = 8 and x2 = 10 and y2 = 10

Now let's plug in these values in the mid-point formula and find (x1, y1)

9 = \frac{x_1 + 10}{2} ; 8 = \frac{y_1 + 10}{2}

Let's simplify and find the value of x1 and y1

18 = x_1 + 10 ; 16 = y_1 + 10\\

x_1 = 18 -10 ; y_1 = 16 -10

x_1 = 8 ; y_1 = 6

So the coordinates of R(8, 6)

3 0
3 years ago
Read 2 more answers
Simplify this PLEASE<br>​
Advocard [28]

Answer:

\frac{12a-14b}{21}

Step-by-step explanation:

Express the 2 fractions with a common denominator of 21

multiply numerator/denominator of first fraction by 3

multiply numerator/denominator of second fraction by 7

\frac{4a(3)}{7(3)} - \frac{2b(7)}{3(7)}

= \frac{12a}{21} - \frac{14b}{21}

= \frac{12a-14b}{21}

4 0
3 years ago
Ellen writes 2 pages in a hour. Determine the equation that represents the function and state it graphically.
Eduardwww [97]

Answer:

1 page every 0.5hours, or 1 page every 30 minutes. The equation is

2x = y

7 0
3 years ago
I really really need help with this..
shtirl [24]
I feel really bad because this is hard and no one is helping you so try using this website it is called wolfram alpha and if you can't find help on that website just ask your teacher for help. I'm sorry I feel bad for you!
6 0
3 years ago
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