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2 years ago

In the diagram, the length of segment TQ is 40 units.

Mathematics

2 answers:

allsm [11]2 years ago

8 0

Answer:

The answer is 44.

Step-by-step explanation:

stiks02 [169]2 years ago

8 0

Answer:

40 units

Step-by-step explanation:

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Help me in major bed of some help

zzz [600]

It would be on both planes. When two planes intersect, they form a line along the points at which the two exist in the same place. Point V is said to exist along line s, which came from the intersection of the planes. This means that the point belongs to both of them.

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3 years ago

HELP!!!!

OverLord2011 [107]

Answer:

Step-by-step explanation:

You just need the distance formula here. It's very simple to follow:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

which, for us, looks like this:

$d=\sqrt{(13-4)^2+(19-7)^2}$ and

$d=\sqrt{9^2+12^2}$ and

$d=\sqrt{81+144}$ and

$d=\sqrt{225}$ so

d = 15

4 0

3 years ago

Honey and Money are twin brothers. Mother wants to equally divide a rectangular shaped cake of 5cm wide and 6cm long. Find the l

tatuchka [14]

Answer:

Length of rectangular cake = 5 cm

Breadth of rectangular cake = 6 cm

Area of rectangle = 5 cm × 6 cm =30 cm²

If cake is equally distributed between Honey and Money, then areas of two parts should be equal.

So, Amount of cake that Honey and money got $\frac{30}{2}=15$

Share of each (Honey and Money)=15 cm²

So, if the third cake if it was cut diagonally ,the cake must have some height.

Let the height of cake be H.

So, Height of third cake $=\sqrt{L^2+B^2+H^2}\\\\=\sqrt{5^2+6^2+H^2}\\\\=\sqrt{61+H^2}$

If , H=0 that is height is negligible having 0 thickness,

Then the Length of third cake, which is divided into two parts=√61=7.81 cm

5 0

3 years ago

Help no troll answer plz

stealth61 [152]

Answer:

Step-by-step explanation:

Q 4. (25m + 25m) ÷ 25 sec. = 2 m/sec.

Q 5. This question belongs to Physics and not Mathematics!!!

Wavelength (lambda) = Velocity (v) ÷ Frequency ( $sec^{-1}$ or Hz )

f = v / (lambda)

f = 3 / 2 = 1.5 (Hz)

Q 6. 0.060 ÷ 2 = 0.030 m

7 0

2 years ago

Question 13

ArbitrLikvidat [17]

Answer:

Step-by-step explanation:

Here in this question , we are interested in calculating the total distance covered by the train in the 10 minutes that it ran.

From the first part of the question, we already know the distances in the first 5 minutes.

Now, to calculate the total distance in the second 5 minutes, we use the distance formula since we have the average speed and the time;

Mathematically; Total distance = average speed * time

From the question, average speed is 33km/h, while time is 5 minutes. To achieve a consistent unit, we convert 5 minutes to hours.

That would be 5/60 = 1/12 hours

So the total distance in the second 5 minutes is;

33 * 1/12 = 2.75 km

Now, to calculate the total distance traveled, let’s add up the distances in the first 5 minutes and convert to kilometers;

That would be;

68 + 127 + 208 + 312 + 535 = 1,250 m

Let’s convert this to km.

We simply divide by 1000 = 1250/1000 = 1.25 km

The total distance is thus ;

1.25 + 2.75 = 4 km

4 0

3 years ago