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liubo4ka [24]
3 years ago
12

How can one determine the number of x-intercepts of the graph of a quadratic function without graphing the function?

Mathematics
1 answer:
velikii [3]3 years ago
5 0

Answer:

The easiest method is to find the x-intercepts of the quadratic function by substituting y=0 in the function and solving it to find the possible values of x. The number of all possible values of x is the number of x-intercepts of the graph.

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Multiply<br> your answer should be in a monomial standard form<br><br> (7h^3)(3h^7)
KonstantinChe [14]

Answer:

21 h^10

Step-by-step explanation:

(7h^3)(3h^7)

Lets multiply

7*3  h^3 h^7

When the bases are the same , we add the exponents (x^a * x^b) = x ^ (a+b)

21 h^(3+7)

21 h^10

5 0
3 years ago
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There are 49 counters in a bag.
emmainna [20.7K]
Answer:

Explanation:

49-20=29 blue counters

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4 0
3 years ago
What is the answer ?
Mashcka [7]
Hi there! The answer is A.
f(x) = - 2 {x}^{2}

In the graph we can see is a parabola (so B. cannot be the answer) with a vertex at the point (0, 0), which means the parabola is not translated upwards or downwards. Therefore, only A. can be correct, since all the other formulas include a translation downwards (which can be deduced from the -2 in the formula).
3 0
3 years ago
Complete the equation of the line through (-6,5)(−6,5)left parenthesis, minus, 6, comma, 5, right parenthesis and (-3,-3)(−3,−3)
sladkih [1.3K]

Answer:

The equation of the line passing through the given points is:

y=-\frac{8}{3}x-11

Step-by-step explanation:

Given:

The two points are: (x_1,y_1)=(-6,5)\textrm{ and }(x_2,y_2)=(-3,-3)

The equation of a line when two points are given is:

y-y_1=\left (\frac{y_2-y_1}{x_2-x_1} \right )(x-x_1)

Plug in all the values and simplify.

y-5=\left (\frac{-3-5}{-3-(-6)} \right )(x-(-6))\\y-5=\left (\frac{-8}{-3+6} \right )(x+6)\\y-5=\left (\frac{-8}{3} \right )(x+6)\\y-5=\frac{-8}{3}x-16\\y=\frac{-8}{3}x-16+5\\\\y=-\frac{8}{3}x-11

Therefore, the equation of the line passing through the above points is

y=-\frac{8}{3}x-11

7 0
3 years ago
Plot the line for the equation on the graph. y−2=−2(x+4)
vitfil [10]
X=3 
y=-12
hope i helped
6 0
3 years ago
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