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prohojiy [21]
2 years ago
15

Let be a circle

with centre O. A second circle L passes through O and cuts K at two other points A and B. Let P be a point on arc AOB and extend line segment BP to intersect K at a second point Q. Prove that the bisector of angle APQ passes through O.
Mathematics
1 answer:
yan [13]2 years ago
8 0

The bisector of angle APQ passes through O and this is illustrated below.

<h3>How to illustrate the information?</h3>

From the information given, the center is O. and the circle passes through O and cuts at K.

In this case, it should be noted that the circles are equal according to the SAS test.

Here, AOB + APQ = 180° (Linear pair)

2AOB = 180

AOB = 90.

Therefore, the bisector of angle APQ passes through O.

Learn more about bisector on:

brainly.com/question/11006922

#SPJ1

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Jason ordered the numbers −70, −18, and −18.5 from least to greatest by writing the following statement:
ser-zykov [4K]

Answer:

No

Step-by-step explanation:

For negative numbers, the larger the number is the smaller its value is. For example -18 is greater than -18.5. This is because -18 is closer to 0 than -18.5 is. If you were to plot -18 and -18.5 on a number line you would see that -18 is closer to 0.

8 0
3 years ago
6^2 + x - x^2 for x=3 <br> help me pls
Stels [109]

Answer:

30

Step-by-step explanation:

Just insert the value of x into the equation.

x = 3 right?

6^2 + 3 - 3^2 because x = 3

36 + 3 - 9 = 39 -9 = 30

:D

4 0
3 years ago
Factor completely 8x5 2x4 4x2. Prime 2(4x5 x4 2x2) 2x(4x4 x3 2x) 2x2(4x3 x2 2).
Alecsey [184]

The complete factor of the expression \rm 8x^5 + 2x^4 + 4x^2 is \rm 2x^{2} (4x^3 + x^2 + 2 )correct option is D.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is \rm 8x^5 + 2x^4 + 4x^2.

To solve the expression properly we have to take common (2x²). Then we have

\rm 8x^5 + 2x^4 + 4x^2\\\\2x^{2} (4x^3 + x^2 + 2 )

The factor is \rm 2x^{2} (4x^3 + x^2 + 2 ).

More about the factorization link is given below.

brainly.com/question/6810544

4 0
2 years ago
How do you find the derivative of 1/logx?
valentina_108 [34]

The derivative of 1/logx is With the chain rule.

1log(x)=log(x)−1 is ,= -1xlog(x)2 .

The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".

The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

With the chain rule. \\ 1log(x)=log(x)−1  \\ So you follow the chain rule to the electricity after which to the log: \\ ddxlog(x)−1=−1⋅log(x) \\  \\−2⋅ddxlog(x)  \\ =−1log(x)21x  \\ =−1xlog(x)2 .

Read more about derivatives;

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5 0
9 months ago
Can someone help me with these? WILL GIVE BRAINLIEST
Ganezh [65]

Answer:

1) no; 202 + 212 ≠ 282

2) yes; 142 + 482 = 502

3) 2

4)18.0

6 0
2 years ago
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