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3 years ago

The gradual increase in activity over time is called

Physics

2 answers:

Ad libitum [116K]3 years ago

7 0

The gradual increase in activity over time is called progression

Sedbober [7]3 years ago

4 0

Answer:Progression is the way in which an individual should increase the load. It is a gradual increase either in frequency, intensity, or time or a combination of all three components.

Explanation:

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Wave 1 displaces according the function f(θ)= 2sin θ+1. Wave 2 displaces according to the function f(θ)= 3sin θ+.5. At what angl

r-ruslan [8.4K]

Answer:

θ = 30⁰

Explanation:

We have been given two wave displacement equations,

$y_{1} =2sin\theta +1$ ........(1)

$y_{2}=3sin\theta +0.5$ ........(2)

The waves will have same displacements when $y_{1}=y_{2}=y$ (say)

Therefore, operating (2) - (1), we get,

$sin\theta - 0.5=0$

or, $\theta = sin^{-1}(0.5)=30^{o}$ (since, sin 30⁰ = 0.5)

We can check the answer by putting $\theta=30^{o}$ in equations (1) and (2),

$y_{1}=2sin30^{o}+1=2\times0.5 + 1= 2$

$y_{2}=3sin30^{o}+0.5=3\times0.5+0.5=1.5+0.5=2$

6 0

3 years ago

Read 2 more answers

A 4400 W motor is used to do work. If the motor is used for 200 s, how much work could it do? (Power: P = W/t)

Inga [223]

Hope this helps, have a great day ahead!

7 0

3 years ago

Read 2 more answers

A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an ampl

Sati [7]

Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.

4 0

3 years ago

600 kg elephant runs at 5 m/s and jumpts onto a 100kg cart. If the coefficient of friction is .04 how far will the cart travel o

Minchanka [31]

Answer:

Eleven seconds.

Explanation:

Two keys are needed to solve this problem. First, the conservation of momentum: allowing you to calculate the cart's speed after the elephant jumped onto it. It holds that:

$m_ev_e+m_c\cdot0=(m_e+m_c)v_0\implies \\v_0=\frac{m_ev_e}{m_e+m_c}=\frac{600kg\cdot 5\frac{m}{s}}{700kg}=4.29\frac{m}{s}$

So, once loaded with an elephant, the cart was moving with a speed of 4.29m/s.

The second key is the kinematic equation for accelerated motion. There is one force acting on the cart, namely friction. The friction acts in the opposite direction to the horizontal direction of the velocity v0, its magnitude and the corresponding deceleration are:

$F_r = 0.04\cdot (m_e+m_c)g\implies a_r = 0.04\cdot g= 0.04 \cdot 9.8 \frac{m}{s^2}=0.39\frac{m}{s^2}$

The kinematic equation describing the decelerated motion is:

$v = -a_r t+v_0\\0 = -a_rt+v_0\implies \\t = \frac{v_0}{a_r}=\frac{4.29\frac{m}{s}}{0.39\frac{m}{s^2}}=11s$

It takes 11 seconds for the comical elephant-cart system to come to a halt.

7 0

4 years ago

An exothermic reaction is taking place in a test tube what would you expect to feel when you touch the outside of the test tube

ValentinkaMS [17]

Answer:

Heat, Let me explain,

Explanation:

An exothermic reaction is like... Lighting a candle so it produces a small amount of heat in less than a second and then normal heat.

7 0

4 years ago