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charle [14.2K]
3 years ago
12

An exothermic reaction is taking place in a test tube what would you expect to feel when you touch the outside of the test tube

Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

Heat, Let me explain,

Explanation:

An exothermic reaction is like... Lighting a candle so it produces  a small amount of heat in less than a second and then normal heat.

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Which type of thermal energy transfer does a wrapping of cotton or plastic reduce the most, conduction, convection, radiation, t
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Answer: Thermal Energy is energy resulting from the motion of particles; It is a form of kinetic energy and is transferred as heat; Thermal Energy Transfer can occur by three methods: Conduction; Convection; Radiation; Conduction. Conduction is the transfer of thermal energy through direct contact between . particles of a substance.

Explanation:

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3 years ago
If the tire reaches a temperature of 48 ∘c, what fraction of the original air must be removed if the original pressure of 250 kp
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Assuming air as ideal gas and amount of air in no of moles is known then by gas law,

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_________ are exchanged or shared during the formation of a chemical bond.
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When waves enter a denser medium, they bend the normal.<br><br> A) Toward<br> B) Away From
Andreyy89
The answer is bend towards normal.
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3 years ago
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A bullet glider and a target glider both have a mass of 0.200 kg. The bullet glider is moving 0.450 m/s
Romashka [77]

Answer:

the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Explanation:

When the two gliders collide, the mobile glider will transfer a bit of time to the fixed glider, which is why it comes out with a speed that is smaller than that of the bullet glider.

Changes can occur that the gliders unite and move with a cosecant speed less than the initial one.

The whole process must be analyzed using conservation of the moment.

             p₀ = m v₀

celestines que clash case

             p_f = (m + M) v

             po = pf

             m v₀ = (n + M) v

             v = \frac{m}{m+M}

calculemos

            v= \frac{0.200}{0.200+M} 0.450

            v= 0.09 m/s

elastic shock case

           p₀ = m v₀

           p_f = m v₁ +M v₂

           p₀ = p_f

           m v₀ = m v₁ + m v₂

6 0
3 years ago
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