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charle [14.2K]
3 years ago
12

An exothermic reaction is taking place in a test tube what would you expect to feel when you touch the outside of the test tube

Physics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer:

Heat, Let me explain,

Explanation:

An exothermic reaction is like... Lighting a candle so it produces  a small amount of heat in less than a second and then normal heat.

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A car with a mass of 3 Kg and velocity of 40 m/s collided with a truck of a velocity of 60 m/s, if the momentum is conserved wha
Luden [163]

Answer:

the mass of the truck is 2 kg.

Explanation:

Given;

mass of the car, m₁ = 3 kg

initial velocity of the car, u₁ = 40 m/s

initial velocity of the truck, u₂ = 60 m/s

let the mass of the truck = m₂

Apply the principle of conservation of linear momemtum;

m₁u₁ = m₂u₂

m₂ = (m₁u₁) / u₂

m₂ = (3 x 40) / (60)

m₂ = 2 kg

Therefore, the mass of the truck is 2 kg.

4 0
3 years ago
What makes music different from noise?
Zepler [3.9K]

the answers going to be A

5 0
3 years ago
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You guys cant answer a dam question I ask it fricking 6th grade questions
nexus9112 [7]

Answer:

calm down please its not that serious maybe no one saw it yet

Explanation:

7 0
3 years ago
Consider the He–Ne laser beam with power P = 0.5 mW, and wavelength in vacuum λo = 632.8 nm, as it travels in the x-direction in
mario62 [17]

Answer:

Explanation:

Power P = .5 mW = .5 x 10⁻³

P = Emax²   / 2μo x c , c is velocity of light , μo is permeability of air .

Emax² = P x 2μo x c

=  .5 x 10⁻³  x 2 x 4π x 10⁻⁷ x 3 x 10⁸

= 37.68 x 10⁻²

Emax = 6.14 x 10⁻¹

= .614 v/m

b) Bmax = Emax  / c

= .614  / 3 x 10⁸

= .2046 x 10⁻⁸ T  

= 20.46 x 10⁻¹⁰ T.

6 0
3 years ago
An elevator of mass m is initially at rest on the first floor of a building. It moves upward, and passes the second and third fl
TEA [102]

Answer:

6. W = 3 m g h

Explanation:

Displacement in moving from first floor to the fourth floor is 3h, and the total energy consumed in this process is (3.m.g.h) which is equal to the work done.

According to the work-energy equivalence the change in energy of a system is equal to the work done.

Here, change in potential energy:

\Delta PE=m.g(\Delta h)

\Delta PE=3mgh

\therefore W=\Delta PE

W=3mgh

5 0
3 years ago
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