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sattari [20]
2 years ago
12

Please help meeeeeeeeeeeeeeeeeeeeeeeeeeee

Mathematics
2 answers:
myrzilka [38]2 years ago
5 0

\\\text{Given that,}~~a_1  =-3\\\\a_n = 3a_{n-1} +5 \\\\a_2 = 3a_{2-1} +5 = 3a_1 +5 = 3(-3) +5 = -9 +5 =-4\\\\a_3 = 3a_{3-1} +5  =3a_2 +5 = 3(-4) +5 = -12 +5 =-7\\\\a_4 = 3a_{4-1} +5 = 3a_3 +5  = 3(-7) +5 = -21+5=-16\\\\\\-3,-4,-7,-16....

Contact [7]2 years ago
4 0

Ok don't hurt yourself I'm here ...

a(n) =  3a(n - 1) + 5

_____________________________________________

<h2>n = 2</h2>

put 2 instead of any "n" you can see in the above equation

a(2) = 3a(2 - 1) + 5

a(2) = 3a(1) + 5

Oh can you see that " a(1) " we know what it is :

a(1) =  - 3

So :

a(2) = 3 \times ( - 3) + 5

a(2) =  - 9 + 5

a(2) =  - 4

_____________________________________________

<h2>n = 3</h2>

put 3 instead of blablabla...

a(3) = 3a(3 - 1) + 5

a(3) = 3a(2) + 5

Oh we just found a(2) so :

a(3) = 3( - 4) + 5

a(3) =  - 12 + 5

a(3) =  - 7

_____________________________________________

<h2>n = 4</h2>

put 4 ...

a(4) = 3a(4 - 1) + 5

a(4) = 3a(3)  + 5huh a(3)

a(4) = 3( - 7) + 5

a(4) =  - 21 + 5

a(4) =  - 16

_____________________________________________

So the first four term of the sequence is :

- 3 \: , \:  - 4 \: , \:  - 7 \: , \:  - 16

There u go...

Have a great day ♡

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