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katrin [286]
3 years ago
9

Given:

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

m∠QPR = 20°

Step-by-step explanation:

If we make a sketch of the triangle, it will be observed, that line R bisects angle P.

Considering Triangle, ΔQPS;

∠QPS=107∘

Considering triangle, QPR;

∠QPR=9x-115∘

Considering triangle, RPS;

∠RPS=4x+27∘

Thus, ∠RPS + ∠QPR = ∠QPS

4x+27° + 9x-115° = 107°

13x - 88° = 107∘

13 x = 107∘ + 88∘

13x = 195°

x = 195°/13

x = 15°

m∠QPR = 9x - 115°

= (9 x 15) - 115°

= 135° - 115°

= 20°

Therefore, m∠QPR = 20°

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lara [203]

Step-by-step explanation:

The problem states that you have a linear function so expect your equation to have this form:

y = mx + b

where m is the slope and b is the y-intercept. You are also given two points: P1(5, 6) and P2(14, 60). Use these points to solve for the slope m.

m = (y2 - y1) / (x2 - x1) = (60 - 6)/(14 - 5)

= 54/9 = 6

So our equation now becomes

y = 6m + b

To solve for b, plug in the values of P1:

6 = 6(5) + b ---> b = -24

Therefore, our equation is

y = 6m - 24

The rest of the points are

(8, 24)

(11, 42)

7 0
2 years ago
Please Complete the page.
Alexxandr [17]
7. -8/3
8. 4/35
9. -21/50
10. 35/64
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6 0
3 years ago
Not sure need help ​
WITCHER [35]

Answer:

the circumference is 31.4159 (or 31.42)

5 0
3 years ago
PLEASE I NEED HELP!!!!!!!!
Yanka [14]

Answer:

1) x= 3i, x= - 3i

2) x= +i\sqrt{7}, x = - i

Step-by-step explanation:

1) x^2+9=0

(x+3i)(x-3i)=0

x= 3i, x=-3i

2) x^2-4=-11

x^2=-7

x= ±i\sqrt{7}

x= +i\sqrt{7}, x = - i

hope this helps!! :))

7 0
2 years ago
What is the common point between lines y = -x + 7 and y = 3x + 10?
neonofarm [45]
Did you figure it out yet? lol
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3 years ago
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