Answer:
I and III only
Step-by-step explanation:
Answer:
y = 9√3
x = 18
Step-by-step explanation:
taking 30 as reference angle
b = y
p = 9
h = x
so
tan30 = p/b
1/√3 = 9/b
or, b = 9√3
so
Answer:
Minimum < Q1 < Median < Q3 < Maximum.
Step-by-step explanation:
We need to summarize using the five-number summary.
First, we need to arrange Minimum, Maximum, Median, Q1, and Q3 in ascending order.
The smallest value would be the Minimum value of the data.
The second minimum will be Q1.
The third minimum will be Median because the median is the mid-value of Q1 and Q3. We also call median Q2.
The fourth value would be Q3 and the largest value would be maximum.
A.
(g*f) (3)
2(3x+2)^2
2(3(3)) ^2
2(9)^2
2*81
162
B.
3(2x^2)+2
6x^2+2
Diagonal of a Rhombus are perpendicular & intersects in their middle point:
Assume the diagonals intersects in H
A(0,-8), B(1,-0), C(8,-4) & D(x, y) are the vertices of the rhombus and we have to calculate D(x, y)
Consider the diagonal AC. Find the coordinate (x₁, y₁) H, the middle of AC
Coordinate (x₁, y₁) of H, middle of A(0,-8), C(8,-4)
x₁ (0+8)/2 & y₁=(-8-4)/2 ==> H(4, -6)
Now let's calculate again the coordinate of H, middle of the diagonal BD
B(1,-0), D(x, y)
x value = (1+x)/2 & y value=(y+0)/2 ==> x= (1+x)/2 & y=y/2
(1+x)/2 & y/2 are the coordinate of the center H, already calculated, then:
H(4, -6) = [(1+x)/2 , y/2]==>(1+x)/2 =4 ==> x=7 & y/2 = -6 ==> y= -12
Hence the coordinates of the 4th vertex D(7, -12)
