Answer: parallelogram
Step-by-step explanation: hope I helped :)
<span>To solve this equation we
can first assume that both a and b are nonzero real numbers. Hence,
A = 1 b = 1
<span><span>
1.
</span>2 (1) + 1 =
2(1)</span>
<span><span>
2.
</span><span> 2 + 1 = 2: now this a false equation since
there is not equality, the equation cannot retain the equal sign but will
become 2 + 1 > 2. Leaving the relationship unequal.
</span></span>However, the alternative to
this problem is to be b = 0. To oversee the rule in order to solve the equation
retaining it as an “equation”. Further, there is no other solution for this
equation.
A = 1 b = 0
<span>1.
Which
becomes 2(1) + 0 = 2(1)</span>
<span><span>
2.
</span><span> 2 + 0 = 2 :
3. 2 = 2. Here we can observe the
equality. </span></span>
</span>
You have to divide the fractions by the numbers
Answer:
C. f has a relative maximum at x = 1.
Step-by-step explanation:
A. False. f(x) is concave down when f"(x) is negative. f"(x) is the tangent slope of the graph, f'(x). So f(x) is concave down between x = -1.5 and x = 1.5.
B. False. f(x) is decreasing when f'(x) is negative. So f(x) is decreasing in the intervals x < -3 and 1 < x < 2.
C. True. f(x) has a relative maximum where f'(x) = 0 and changes from + to -.
Answer:
3
Step-by-step explanation:
it is the correct answer
