Answer:
x = infinite amount of solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define Equation</u>
2(x + 4) = 4x + 3 - 2x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute 2: 2x + 8 = 4x + 3 - 2x + 5
- Combine like terms: 2x + 8 = 2x + 8
- Subtract 8 on both sides: 2x = 2x
- Divide 2 on both sides: x = x
Here we see that <em>x</em> does indeed equal <em>x</em>.
∴ x = infinite amount of solutions
Simplify \frac{21}{2}x
2
21
x to \frac{21x}{2}
2
21x
\frac{21x}{2}-\frac{3}{4}(2x+5)=\frac{3}{8}
2
21x
−
4
3
(2x+5)=
8
3
2 Simplify \frac{3}{4}(2x+5)
4
3
(2x+5) to \frac{3(2x+5)}{4}
4
3(2x+5)
\frac{21x}{2}-\frac{3(2x+5)}{4}=\frac{3}{8}
2
21x
−
4
3(2x+5)
=
8
3
3 Multiply both sides by 44 (the LCM of 2, 42,4)
42x-3(2x+5)=\frac{3}{2}42x−3(2x+5)=
2
3
4 Expand
42x-6x-15=\frac{3}{2}42x−6x−15=
2
3
5 Simplify 42x-6x-1542x−6x−15 to 36x-1536x−15
36x-15=\frac{3}{2}36x−15=
2
3
6 Add 1515 to both sides
36x=\frac{3}{2}+1536x=
2
3
+15
7 Simplify \frac{3}{2}+15
2
3
+15 to \frac{33}{2}
2
33
36x=\frac{33}{2}36x=
2
33
8 Divide both sides by 3636
x=\frac{\frac{33}{2}}{36}x=
36
2
33
9 Simplify \frac{\frac{33}{2}}{36}
36
2
33
to \frac{33}{2\times 36}
2×36
33
x=\frac{33}{2\times 36}x=
2×36
33
10 Simplify 2\times 362×36 to 7272
x=\frac{33}{72}x=
72
33
11 Simplify \frac{33}{72}
72
33
to \frac{11}{24}
24
11
x=\frac{11}{24}x=
24
11
X=11 over 24
D I think that’s the answer as dark chocolate takes longer to melt then white
Answer
The solution set includes all numbers less than or equal to 199.There should be a closed circle at 199 then have an arrow pointing towards the left.Negative solutions do not make sense for the situation.
Step-by-step explanation:
Answer:light
Step-by-step explanation:The independent variable is the condition that you change in an experiment. It is the variable you control. It is called independent because its value does not depend on and is not affected by the state of any other variable in the experiment.
