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yKpoI14uk [10]
3 years ago
10

If the measure of 1 is x and the measure of <2 is x+50, what is the measure of <4?

Mathematics
1 answer:
marin [14]3 years ago
7 0

Answer:

Measure of angle 4 is 115°

Step-by-step explanation:

First, we want to find the measure of angle 2, because the measure of angle 2 is equal to angle 4. When 2 straight lines cross each other, the angles formed are always equal to the angle right across from it.

Find angle 2 by setting up an equation:

x+x+50=180

This is basically saying that angle 1 plus angle 2 equals 180°. In a half turnaround, the angle is 180°. Angle 1 and 2 make up a half turnaround.

Solve the equation:

x+x+50=180

Combine the 2 x's to get 2x.

2x+50=180

Subtract 50 from both sides.

2x=130

Divide both sides by 2.

x=65

Since x=65, plug 65 into x in the measure of angle 2 (x+50).

65+50=115.

Since Angle 2 is equal to angle 4, angle 4 is also 115.

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X 2 +10x+22=13x, squared, plus, 10, x, plus, 22, equals, 13 1) Rewrite the equation by completing the square. Your equation shou
Masteriza [31]

Answer:

(x + 5)^2 = (5 - 3)^2

Step-by-step explanation:

Given the equation;

x^2 + 10x + 22 = 13

We have;

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5 0
3 years ago
Read 2 more answers
EDIT// answer below thank for the help -.-
HACTEHA [7]

Step-by-step explanation:

Move it it up 4 and then find your x intercepts.

Find the x intercepts.

-x^2 + 4 = 0

<u>Move the 4 over to the right</u>

-x^2 = -4

<u>Divide out the - </u>

\frac{-x^2}{-} = \frac{-4}{-}

x^2 = 4

<u>Take the square root of each side</u>

\sqrt{x^2} = \pm \sqrt{4}

x = \pm \sqrt 2

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8 0
3 years ago
How do you simplify this
Dafna11 [192]

Top:

x / (x + 1) - 1 / x

= [x^2 - (x +1)] / x(x+1)

= (x^2 - x - 1 ) / x (x+1)

Bottom:

x / (x + 1) + 1 / x

= [x^2 + (x +1)] / x(x+1)

= (x^2 + x + 1 ) / x (x+1)

Now you have:

(x^2 - x - 1 ) / x (x+1)

----------------------------

(x^2 + x + 1 ) / x (x+1)

= (x^2 - x - 1 ) / x (x+1) * x (x+1) / (x^2 + x + 1 )

= (x^2 - x - 1 ) /(x^2 + x + 1 )

Answer:

x^2 - x - 1

---------------------

x^2 + x + 1

7 0
3 years ago
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