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Elenna [48]
2 years ago
14

Equivalent fractions

Mathematics
1 answer:
lyudmila [28]2 years ago
3 0

Answer:

number 1. 5/4  number 2.  7/4 number 3. 1/5

Step-by-step explanation                                                                                           It's the shaped parts. Hope this helps : )

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the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr
Naily [24]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}

\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
5 0
4 years ago
Read 2 more answers
Question 18<br> Decrease £4600 by 20%
NISA [10]

Answer:

3680

Step-by-step explanation:

So, we would subtract. But, first we have to find the percent. But, we all use calculators so, it is 920. Saves us a lot of time.

4600 - 920 = 3680

Therefore your answer is 3680

Hope this helps!

4 0
3 years ago
Write as a product:<br><br> a^3-m^3 n^9
weeeeeb [17]

Answer:

=−m3n9+a3

Step-by-step explanation:

Let's simplify step-by-step.

a3−m3n9

=a3+−m3n9

4 0
2 years ago
Help me with this plz
liberstina [14]
1/2 * 1/4 = 1/8
3/8 * 2/3 = 1/4 same for back left fin
2/5 *1/2 = 1/5
2/3 *1/2 = 1/3
1/4 + 3/4 = 8/8
2/3 +1/6 = 5/6
4/5 +1/5 = 4/4
1/4 +1/5 = 9/20
front/back right fin = 3/8
x+ 1 2/3..... = 4/5


8 0
3 years ago
At a certain time of day, a 5 foot tall man has an 8 foot shadow. If a tree is 20 feet tall, what is the distance between the tr
Leto [7]
If they're asking the distance between the tree and the man's shadow, that would be 12ft and if they're asking the distance between the tree and the actually man, that would be 15ft :).
5 0
3 years ago
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