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3 years ago

Solve the inequality. 4│x + 5│ - 2 ≤ 10

Mathematics

2 answers:

castortr0y [4]3 years ago

6 0

Step-by-step explanation: To solve this absolute value inequality,

our goal is to get the absolute value by itself on one side of the inequality.

So start by adding 2 to both sides and we have 4|x + 5| ≤ 12.

Now divide both sides by 3 and we have |x + 5| ≤ 3.

Now the the absolute value is isolated, we can split this up.

The first inequality will look exactly like the one

we have right now except for the absolute value.

For the second one, we flip the sign and change the 3 to a negative.

So we have x + 5 ≤ 3 or x + 5 ≥ -3.

Solving each inequality from here, we have x ≤ -2 or x ≥ -8.

kati45 [8]3 years ago

3 0

Answer:

4x+20 -2<10

4x+18+10

4x+28

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3 years ago

(m? - 5 m +6 )<br>÷(m - 2)

leonid [27]

Answer:

(m? - 5 m +6 ) ÷ (m - 2) = $\frac{m}{-5m+6} / (m - 2)$

Step-by-step explanation:

Divide the first expression by the second expression.

$\frac{m}{-5m+6} / (m - 2)$

I hope this helps.

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3 years ago

Read 2 more answers

Use properties of operations to write an expression equivalent to the sum of the expressions 3(g + 5) and 2(3g - 6)

melisa1 [442]

Well, you would istribute
using
a(b+c)=ab+ac
so

3(g+5)=3(g)+3(5)=3g+15
2(3g-6)=2(3g)+2(-6)=6g-12

now we gots
3g+15+6g-12
using commutative, we can arrange and group like terms because
a+b=b+a
so
3g+6g+15-12
add
9g+3

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3 years ago

What is the quotient (2x^3 + 3x - 22) / (x-2)

Scilla [17]

Answer:

The quotient is 2x^2+4x+11

Step-by-step explanation:

6 0

3 years ago

find the slope of the curve y=x^2-2x-5 at the point P(2,5) by finding the limit of secant slopes through point P

Fynjy0 [20]

The point (2, 5) is not on the curve; probably you meant to say (2, -5)?

Consider an arbitrary point Q on the curve to the right of P, $(t,y(t))=(t,t^2-2t-5)$ , where $t>2$ . The slope of the secant line through P and Q is given by the difference quotient,