Answer:
To find the answer, you must multiply/divide the amount in cups by calories per cup.
Step-by-step explanation:
Butter only has 0.3 cups, so The calories will only be 30% of what is written down. 30% of 1627= <u>488.1 calories</u>
Marshmallows is 4.25 times larger then the calories per cup, so now you'll have to multiply.
4.25*159=<u>675.75 calories</u>
Finally, Cereal is 5.5 times larger then the calories per cup, so we will multiply again.
5.5*101=<u>555.5 calories</u>
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Finally, add all the number together to find the total amount of calories in the marshmallow treats.
555.5+675.75+488.1=<u>1,719.35 calories</u>
There is a total of 1,719.35 calories in the marshmallow treats.
Answer:
x = (-5 ± 2√10) / 3
Step-by-step explanation:
5 − 10x − 3x² = 0
Write in standard form:
-3x² − 10x + 5 = 0
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-10) ± √((-10)² − 4(-3)(5)) ] / 2(-3)
x = [ 10 ± √(100 + 60) ] / -6
x = (10 ± 4√10) / -6
x = (-5 ± 2√10) / 3
I'm afraid I'm unable to answer your question. Do you have an attachment of the conversation? If so, can you attach it? It'll help me to better answer your question.
The answer is 19
work :
1-multiply the numbers by a submultiple of 10 to remove the decimal points.
2-
now do the division :
so the answer is 19
note: there is no need to get it back to decimal number unless you multiply just one of the numbers or multiply the numbers with different submultiples of 10
good luck
y = ax^2 + 10x + 1
For our graph, y = 0 whenever it crosses the x-axis, so we must solve:
0 = ax^2 + 10x + 1
Using the quadratic formula:
[-10 ± sqrt(100 - 4a)]/(2a)
In order to have two distinct roots, our square root part of the answer above must be a real number that is not zero. In other words:
100 - 4a > 0
Because if the value underneath the square root symbol is negative, we will have no solution, and if the value underneath the square root symbol is zero, then we will only get one solution.
So solve:
100 - 4a > 0
100 > 4a
25 > a
So a must have a value lower than 25. Also note that when a = 0, we have a linear equation which only has one solution that crosses the x-axis, so we must exclude a = 0 as well.
So the answer is:
a < 25, where a ≠ 0