H = 3b+2
A = (h*b)/2 28 = (3b+2)b/2 56 = 3b²+2b 0 = 3b² + 2b - 56
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![\left \{ {{y=2} \atop {x=2}} \right. \int\limits^a_b {x} \, dx \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \beta \\ \\ \\ x^{2} \sqrt{x} \sqrt[n]{x} \frac{x}{y} x_{123} x^{123} \leq \geq \pi \alpha \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] x_{123} \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}}](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D%20%5Cright.%20%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20a_n%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%5Cbeta%20%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20%20x%5E%7B2%7D%20%20%5Csqrt%7Bx%7D%20%20%5Csqrt%5Bn%5D%7Bx%7D%20%20%5Cfrac%7Bx%7D%7By%7D%20%20x_%7B123%7D%20%20x%5E%7B123%7D%20%20%5Cleq%20%20%5Cgeq%20%20%5Cpi%20%20%5Calpha%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%263%5C%5C4%265%266%5C%5C7%268%269%5Cend%7Barray%7D%5Cright%5D%20%20x_%7B123%7D%20%20%5Cint%5Climits%5Ea_b%20%7Bx%7D%20%5C%2C%20dx%20%20%5Cleft%20%5C%7B%20%7B%7By%3D2%7D%20%5Catop%20%7Bx%3D2%7D%7D)
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Answer:
• for x = 2a√t, make t the subject:

• then find y:

Answer:
h = 9 units of length
Step-by-step explanation:
Volume of a circular right cone is:
V(c) = (1/3)*Area of the circular base * h
Where h is the height of the cone, then
V(c) = (1/3) * π * r² * h
And we have that V(c) = 108*π
Then:
108 * π = (1/3) * π * r² * h (1)
We know diameter of the circular base is 12 units, according to that
r = d/2 ⇒ r = 12/2 r = 6 units
Then:
108 * π [ cubic units ] = (1/3) * π * (6)² * h [square units] [ units of length]
When simplifying we have to take into account that in order to keep last equation h needs to have units of length
Therefore:
108 = (1/3) * 36 * h
h = ( 108* 3 )/ 36
h = 9 units of length
It doesn’t represent a function so your answer is B!!
Answer: 5 toy cars
Step-by-step explanation: Hi there.
First, add the number of cars that he had, the number of cars he bought, and the number of cars he received for his birthday: 13+22+21=56
Then subtract your answer (56) from the number of toy cars he gave away to Wayne and his sister: 56-46-5=5
Therefore, Darrel has 5 toy cars left.
Have a nice day! :)