145-13-9-5 that what your looking for
Answer:
10>-15
Step-by-step explanation:
The given inequality is:
-2<3
The inequality has to be multiplied by -5.
The multiplication is same as multiplying a normal equation with a number. The only difference is that the sign of inequality is changed when it is multiplied with a negative number.
So,
-2(-5) < 3(-5)
10>-15
So the correct answer is the last option ..
It’s cool I need help too
The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.
Domain is the values of x in the function represented by y=f(x), for which y exists.
THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".
Now we assume the
and ![f(x)=\frac{1}{x-6}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7Bx-6%7D)
So here since g(x) is a polynomial function so it exists for all real x.
<em> </em>does not exists when
, so the domain of f(x) is given by all real x except 6.
Now,
![(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}](https://tex.z-dn.net/?f=%28fg%29%28x%29%3Df%28g%28x%29%29%3Df%28x%2B2%29%3D%5Cfrac%7B1%7D%7B%28x%2B2%29-6%7D%3D%5Cfrac%7B1%7D%7Bx-4%7D)
So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.
But domain of both f(x) and g(x) consists of the value x=4.
Hence the statement is not TRUE universarily.
Thus the given statement about the composition of function is FALSE.
Learn more about Domain here -
brainly.com/question/2264373
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