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Sergeu [11.5K]
3 years ago
12

The probability of rolling two six-sided dice and having the sum on the two dice equal 7 is . You roll two dice six times. Are y

ou guaranteed to get a sum of 7 once?
Mathematics
1 answer:
n200080 [17]3 years ago
7 0

Probabilities are used to determine the chances of events

It is not guaranteed to have a sum of 7 once in 6 rolls

The probability is given as:

Pr = \frac 16

The number of rolls is:

n = 6

The expected value of having a sum of 7 is calculated using:

E(x) =np

So, we have:

E(x) =6 \times \frac 16

E(x) =1

This means that, in 6 rolls of 2 dice, it is expected to have a sum of 7 once; however, it is not guaranteed.

Hence, it is not guaranteed to have a sum of 7 once;

Read more about probabilities at:

brainly.com/question/251701

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Answer:

sum is 125,500

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Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

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_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

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