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RoseWind [281]
2 years ago
5

F(X) = 3X – 4 THE DOMAIN FOR THE FUNCTION IS {1, 2, 3} WHAT IS THE RANGE?

Mathematics
1 answer:
Juliette [100K]2 years ago
5 0

Answer:

y = {-1, 2, 5}

although, I am not sure how you want to format your answer

Step-by-step explanation:

just input the values for the domain

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The pair of triangles that are congruent by ASA criterion is
stealth61 [152]

Answer:

The pair of triangles that are congruent by the ASA criterion isΔ ABC and Δ XYZ.

The pair of triangles that are congruent by the SAS criterion is Δ BAC and ΔRQP.

Step-by-step explanation:

Two triangles are congruent by ASA property if any two angles and their included side are equal in both triangles .In triangles Δ ABC and Δ XYZ the equal side 5 is between the two equal angles. So these triangles are congruent by ASA criterion.

Two triangles are congruent by SAS if  two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle .In triangles  Δ BAC and ΔRQP. the included angles A and Q are equal and hence the triangles are congruent by SAS criterion.

4 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
ElenaW [278]

Answer:

8.2

Step-by-step explanation:

(4.5)^2+(6.9)^2=c^2

20.25+47.61=67.86

sqrt of 67.86= 8.2 (rounded already) :)

6 0
2 years ago
Can someone please help me with math.
timurjin [86]

Answer:

Your answer would be B.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
Help me sort out the photo
musickatia [10]
I hope this helps you




2x+5-3x+2=7-x



3x-2-2x-5=x-7


2x+5+3x-2=5x+3
6 0
3 years ago
Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.
Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0
3 years ago
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