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Artyom0805 [142]
3 years ago
13

33/5 divided by 21/4 keep change flip

Mathematics
2 answers:
JulijaS [17]3 years ago
6 0

Answer:

33/5 x 4/21 = 44/35

Step-by-step explanation:


Amanda [17]3 years ago
4 0

Answer: 33/5 x 4/21 = 44/35




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John bought a pack of 18 cards for $2.99. About how much did each card cost?
Iteru [2.4K]

Answer:

0.166

Step-by-step explanation:

Bought 18 cards for $2.99, so you can write it like this:

18 = 2.99

Since you want to find the value of one card, u could write that like this:

1 = x  (where x is the unknown value of 1 card)

To get from 18 to 1, you divide by 18, so to get to 2.99 to x you must divide by 18 as well.

So 2.99/18 = 0.166

therefore x = 0.166

So you can say that each card costs about 17 c

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3 years ago
10 points
vichka [17]

Answer:

i need the answer aswell

6 0
3 years ago
When solving a mass/particle or particle/mass conversion calculation what piece(s)
Lana71 [14]

Answer:

i would cry if i had to do this tbh

Step-by-step explanation:

6 0
3 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
2 years ago
Read 2 more answers
A theatre holds 1200 people when full.If it is 80% full,how many people are present
CaHeK987 [17]

0.8 times 1200 is 960, which is the number of people when the theatre is 80% full.

4 0
3 years ago
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