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Artyom0805 [142]
2 years ago
13

33/5 divided by 21/4 keep change flip

Mathematics
2 answers:
JulijaS [17]2 years ago
6 0

Answer:

33/5 x 4/21 = 44/35

Step-by-step explanation:


Amanda [17]2 years ago
4 0

Answer: 33/5 x 4/21 = 44/35




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Simplify (5 x + 1) - (-10 x + 6)
tekilochka [14]

Answer:15x+7

Step-by-step explanation:

First you would see that the -(-10x+6) would turn into 10x+6 meaning that the whole equation would turn into 5x+1+10x+6. Then add the x numbers together and the whole numbers separate. So now your answer should be 15x+7

8 0
3 years ago
Read 2 more answers
In triangle abc shown below side ab is 6 and side ac is 4
kaheart [24]

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove  that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

7 0
3 years ago
If a diameter intersects a chord of a circle at a perpendicular, what conclusion can be made? The diameter and the chord are con
yarga [219]

Answer:

The chord is bisected ⇒ 3rd answer

Step-by-step explanation:

* Lets revise some facts in the circle to solve the problem

- A chord in a circle is the segments whose endpoints lie on the

 circumference of the circle

- A diameter of a circle is a chord passes through the center of the

 circle

- The diameter is the longest chord in the circle

- Any line passes through the center of the circle and perpendicular

 to a chord on the circle bisects it

* Lets solve the problem

∵ The diameter of the circle passes through the center of the circle

∵ The diameter intersects a chord of a circle at a perpendicular

∴ The diameter is perpendicular to the chord

∵ Any line passes through the center of the circle and perpendicular

  to a chord on the circle bisects it

∴ The diameter bisects the chord

* The chord is bisected

8 0
3 years ago
Read 2 more answers
Fill in the bubble completely to show your answer.
adell [148]

Answers :D18

Step-by-step explanation:

Because I did the marh

4 0
2 years ago
Please help me with this question.
Rufina [12.5K]

 

m∠AOC = 108°

m∠AOC = 3m∠AOB

⇒m∠AOB = (m∠AOC) / 3 = 108 / 3 = 36°



3 0
2 years ago
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