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Lelu [443]
2 years ago
9

Describe the necessary Java commands to create a Java program for creating a lottery program using arrays and methods.

Computers and Technology
2 answers:
netineya [11]2 years ago
5 0
I think each lottery ticket will cost £5 each so you would count in 5s till you reach the amount of tickets to get the answer which is £25
wariber [46]2 years ago
5 0

Answer: would use the for loop in this java program. A for loop is a repetition control structure that allows you to write a loop that needs to be executed a specific number of times which is why it's beneficial for the lottery program. A for loop is useful when you know how many times a task is to be repeated. import java.util.Random;import java.util.Scanner;public class LotteryGame

{  public static void main(String[] args) {     // TODO Auto-generated method stub     

Random r = new Random();     
int random[] = new int[5];   

  for (int i = 0; i < 5; ++i) {   
     random[i] = r.nextInt(48) + 1;     } 

    Scanner


sc = new Scanner(System.in);    
 int usernumbers[] = new int[5];     

System.out.print("Enter 5 numbers: ");  

   for (int i = 0; i < 5; ++i) { 

  usernumbers[i] = sc.nextInt();     }     

System.out.print("\nRandom Numbers: ");    
 for (int i = 0; i < 5; ++i)        

System.out.print(random[i] + " ");  
   System.out.print("\nUser Entered Numbers: ");     for (int i = 0; i < 5; ++i)        

System.out.print(usernumbers[i] + " ");   

  int match = 0;    
 for (int i = 0; i < 5; ++i) {       
 for (int j = 0; j < 5; ++j) {          

 if (random[i] == usernumbers[j])              
++match;        }

     }     
System.out.println("\nThere are " + match + " number of matches");  }

Explanation:

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In the original UNIX operating system, a process executing in kernel mode may not be preempted. Explain why this makes (unmodifi
Elena L [17]

Answer:

the preemption is -> The ability of the operating

system to preempt or stop a currently

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task. The scheduling may be one of, but not

limited to, process or 1/0 scheduling etc.

Under Linux, user-space programs have always

been preemptible: the kernel interrupts user

space programs to switch to other threads,

using the regular clock tick. So, the kernel

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case in cooperative multitasking). This means

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cannot block the system.

However, until 2.6 kernels, the kernel itself was

not preemtible: as soon as one thread has

entered the kernel, it could not be preempted to

execute an other thread. However, this absence

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So, kernel preemption has been introduced in

2.6 kernels, and one can enable or disable it

using the cONFIG_PREEMPT option. If

CONFIG PREEMPT is enabled, then kernel code

can be preempted everywhere, except when the

code has disabled local interrupts. An infinite

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when a driver receives a text while driving, what can 2022 versa’s hands-free text messaging assistant do?
Lena [83]

Answer:

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Explanation:

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3 years ago
What number will be output by the console.log command on line 5?
bagirrra123 [75]

Answer:

The output is 35

Explanation:

Required

Determine the output on line 5

We start by analysing the program line by line.

On line 1: kit = 20

On line 2: roo = 10

On line 3: kit = kit + 5

Substitute 20 for kit.

So, we have

kit = 20 + 5

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On line 4:

roo = kit + roo

Substitute values for kit and too

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On line 5: Output roo

So, 35 is displayed as an output

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