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3 years ago

. wireless network adapters differ from regular networkadapters because theycontain………………..

Computers and Technology

1 answer:

Nataly_w [17]3 years ago

8 0

Answer: Transceivers

Explanation:

Wireless network adapters differ from regular network adapters because they contain transceivers as, the transceiver is that portion of the network interface which transmitted the data by concerting digital data into the digital signals in the medium. Basically, the network adapter are responsible for connected the host in the network medium and also convert the binary form data.Transceiver signal are basically depends upon the type of the network.

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1. Implement a method factorial(int n), that takes a number (int) and returns its factorial. Factorial of an integer is the prod

marysya [2.9K]

Answer:

import java.io.*;

import java.util.*;

public class Main

{

public static int factorial(int n){

if (n == 0)

return 1;

else

return(n * factorial(n-1)); //recursively calling factorial function

}

public static void fibbonaci(int n)

{

if(n>0)

{

c=a+b; //next term in series

a=b;

b=c;

System.out.print(" "+c);

fibbonaci(n-1); //recursively calling fibbonaci function

}

static int a=0,b=1,c;

public static void main(String[] args) {

int list_num,fact;

List<Integer> num=Arrays.asList(1,3,5,7,9); //arraylist with 1,3,5,7,9

for(Integer i:num) //for-each loop

{

a=0;

b=1;

list_num=i.intValue();

System.out.println("Fibbonaci series for "+list_num);

System.out.print(a+" "+b);

fibbonaci(list_num-2); //calling fibbonaci for values in list

fact=factorial(list_num); //calling factorial for values in list

System.out.println();

System.out.println("Factorial for "+list_num+" is "+fact);

System.out.println();

}

6 0

4 years ago

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

$v = \frac{(xf-xo)}{(t-to)}$

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

$t =\frac{xf}{v} =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.$

⇒ t = 8.7*10⁻⁴ sec.

4 0

3 years ago

is skill in using productivity software, such as word processors, spreadsheets, database management systems, and presentation so

Digiron [165]

Answer:

It is general knowledge

Explanation:

What you covered is general knowledge and the entrance to computer science.

4 0

3 years ago

The ______ manages the hardware components including the cpu, memory storage, and peripheral devices. options operating system d

Alexandra [31]

The answer is the os or operating system

8 0

3 years ago

Write a C++ program to grade the answers to a true-false quiz given to students in a course. The quiz consists of 5 true-false q

Eddi Din [679]

The quiz program is an illustration of loops and conditional statements

Loops are used to perform repetition
Conditional statements are used to make decisions

<h3>The quiz program</h3>

The quiz program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

int main(){

//This prints the instruction

cout<<"Enter T/t for True; F/f for False\n";

//This initializes the question

string questions[5] = { "Q1", "Q2", "Q3", "Q4", "Q5"};

//This initializes the correct options

char options[5] = { 'T','T','F','F','T'};

//This declares the user response

char opt;

//This initializes the score to 0

int score = 0;

//This loop is repeated 5 times

for (int i = 0; i < 5; i++){

//This prints the current question

cout << i + 1 <<". "<<questions[i]<<"\nAnswer: ";

//This gets the user response

cin>>opt;

//If the user response is correct

if(toupper(opt) == options[i]){

//The score is incremented by 2

score+=2;

}

//This prints the total score

cout<<"Score: "<<score;

return 0;

}