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statuscvo [17]
3 years ago
13

Find the missing measurements of the right triangle.

Mathematics
1 answer:
svlad2 [7]3 years ago
3 0

Step-by-step explanation:

as always, the sum of all angles in a triangle is always 180°.

therefore, the angle at B is

B = 180 - 27 - 90 = 63°.

for the missing sides we use the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

where the sides are always opposite of the related angles.

so,

AB/sin(90) = 12/sin(27)

since sin(90) = 1, we have

AB = 12/sin(27) = 26.43227118... ≈ 26.4

AC/sin(63) = 12/sin(27)

AC = 12×sin(63)/sin(27) = 23.55132607... ≈ 23.6

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The odds in favor of jim beating a friend at golf are 1:8. find the probability that jim will win.
agasfer [191]

The probability that jim will win = P(A) = 1/9

<h3>What is  probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

<h3>According to the given information :</h3>

The odds in favor of jim beating a friend at golf are =  1:8

Let A be the event that Jim beating a friend golf.

So,

according to ratio, it becomes

P(A)/P(A') = 1/8

P(A) = 1x

P(A')  = 8x

we know that :

P(A) + P(A') = 1

x + 8x = 1

9x = 1

x = 1/9

so that

P(A) = 1/9

P(A')  = 8/9

the probability that jim will win = P(A) = 1/9

To know more about probability visit:

brainly.com/question/10735118

#SPJ4

3 0
2 years ago
What are the integers of 171
Natasha2012 [34]

Answer:

56, 57, and 58.

Step-by-step explanation:

4 0
3 years ago
A particle moves with velocity vector
asambeis [7]

Answer:

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}

Step-by-step explanation:

We are given that velocity vector of a particle

\vec{v(t)}=t\hat{i}-2\hat{j}+t^2\hat{k}

When t=0 then the particle is at the point (0,-1,1).

We have to find the position of particle  at time t.

We know that

Velocity =\frac{Displacement }{time}=\frac{ds}{dt}

Therefore,\vec{v}=\frac{\vec{ds}}{dt}

\int{ds}=\int (t\hat{i}-2\hat{j}+t^2\hat{k})dt

Integrate on both sides then we get

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}+C

\int x^n dx=\frac{x^{n+1}}{n+1}+C

Substitute the value of point at time t=0 then we get

C=-\hat{j}+\hat{k}

Substitute the value of C then we get

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-2t\hat{j}+\frac{1}{3}t^3\hat{k}-\hat{j}+\hat{k}

Therefore, the position of particle at time t

\vec{s(t)}=\frac{1}{2}t^2\hat{i}-(2t+1)\hat{j}+(\frac{1}{3}t^3+1)\hat{k}

8 0
3 years ago
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