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lys-0071 [83]
2 years ago
5

The table shows the final score of four golfers.

Mathematics
2 answers:
AlekseyPX2 years ago
5 0

Answer:

Joe score was the highest. Tara score was the lowest.

Step-by-step explanation:

Igoryamba2 years ago
4 0
Highest is joe because it the most closest to 0
Lowest is Tara because it the most far from 0
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The National Assessment of Educational Progress (NAEP) includes a "long-term trend" study that tracks reading and mathematics sk
daser333 [38]

Answer:

The 99% confidence interval estimate for the proportion of all 17-year-old students in 2012 who had at least one parent graduate from college is (0.4964, 0.5236).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Sample of 9000, 51% of students had at least one parent who was a college graduate.

This means that n = 9000, \pi = 0.51

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.51 - 2.575\sqrt{\frac{0.51*0.49}{9000}} = 0.4964

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.51 + 2.575\sqrt{\frac{0.51*0.49}{9000}} = 0.5236

The 99% confidence interval estimate for the proportion of all 17-year-old students in 2012 who had at least one parent graduate from college is (0.4964, 0.5236).

7 0
2 years ago
9. If one box of books contains 7.5% of the total shipment and each box includes 15 books, how many books are included in the to
Inga [223]

Answer:

210 books

Step-by-step explanation:

Hello

I think  I can help you with this

Step 1

if one box is 7.5% of the total shipment, how many box is the total shipment

1 box =7.5%

x?box=100%

using a rule of three

\frac{1\ box}{7.5 } =\frac{x}{100}

Now, isolating x

\frac{1\ box*100}{7.5 } =x\\x=13.34\ boxes

13.34 boxes is the total

Step 2

find the total  of books

we will need 14 boxes, because it does not exist 0.34  box

so, the total of books=

number of boxes*number of books included in each box

=14 boxes*15 books

=210 books

Have a great day

7 0
3 years ago
A sample of bacteria is being eradicated by an experimental procedure. The population is following a pattern of exponential deca
77julia77 [94]

Answer:

There will be 50 bacteria remaining after 28 minutes.

Step-by-step explanation:

The exponential decay equation is

N=N_0e^{-rt}

N= Number of bacteria after t minutes.

N_0 = Initial number of bacteria when t=0.

r= Rate of decay per minute

t= time is in minute.

The sample begins with 500 bacteria and after 11 minutes there are 200 bacteria.

N=200

N_0 = 500

t=11 minutes

r=?

N=N_0e^{-rt}

\therefore 200=500e^{-11r}

\Rightarrow e^{-11r}=\frac{200}{500}

Taking ln both sides

\Rightarrow ln| e^{-11r}|=ln|\frac{2}{5}|

\Rightarrow {-11r}=ln|\frac{2}{5}|

\Rightarrow r}=\frac{ln|\frac{2}{5}|}{-11}

To find the time when there will be 50 bacteria remaining, we plug N=50, N_0= 500 and  r}=\frac{ln|\frac{2}{5}|}{-11} in exponential decay equation.

50=500e^{-\frac{ln|\frac25|}{-11}.t}

\Rightarrow \frac{50}{500}=e^{\frac{ln|\frac25|}{11}.t}

Taking ln both sides

\Rightarrow ln|\frac{50}{500}|=ln|e^{\frac{ln|\frac25|}{11}.t}|

\Rightarrow ln|\frac{1}{10}|={\frac{ln|\frac25|}{11}.t}

\Rightarrow t= \frac{ln|\frac{1}{10}|}{\frac{ln|\frac25|}{11}.}

\Rightarrow t= \frac{11\times ln|\frac{1}{10}|}{{ln|\frac25|}}

\Rightarrow t\approx 28 minutes

There will be 50 bacteria remaining after 28 minutes.

3 0
3 years ago
The amount A in an account after t years with principal P, annual interest rate r (expressed as a decimal), and compounded n tim
muminat

Answer:

Quarterly: $30.34

Monthly: $30.42

Daily:  $ 30.45

Step-by-step explanation:

8 0
3 years ago
Find the missing angle
sineoko [7]

129 degrees is the correct answer for the missing angle number 1 :)

3 0
2 years ago
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