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2 years ago

Graph the solution to the inequality on the number line. p<20.2 help

Mathematics

1 answer:

IgorC [24]2 years ago

5 0

Answer:

it is an open circle on 20.2 and is going to the left

Step-by-step explanation:

I hope this helps :)

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1) y = 2x – 17 -3x – y=-13

scoray [572]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}y=2x-17&\text{subtract}\ 2x\ \text{from both sides}\\-3x-y=-13\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}-2x+y=-17\\-3x-y=-13\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-5x=-30\qquad\text{divide both sides by (-5)}\\.\qquad\boxed{x=6}\\\\\\\text{Substitute the value of x to the first equation}\\\\y=2(6)-17\\y=12-17\\\boxed{y=-5}$

8 0

3 years ago

Given the slopes of three lines, m1 = 2, m2 = 5. m3 = -4, which line would you say is

bagirrra123 [75]

Compare the slopes of the 4 equations, which is the number in the term with "x". The slope with highest absolute value is the steepest. Positive slope means the function is ascending left to right, negative slope means it is descending left to right. If you only care that it is the steepest, regardless of whether it is ascending or descending, then the answer is (D).

4 0

2 years ago

Read 2 more answers

10b - 5m - 4b +8b - 4m Simplify the expression you combining like terms

Paraphin [41]

Answer:

14b - 9m

Step-by-step explanation:

10b - 4b + 8b - 5m - 4m

14b - 9m

4 0

3 years ago

Y= 2x x+y=12 What is this answer?

morpeh [17]

Answer:

if Y = 2x so place 2x to the why and for it can = 12 well put 10x

6 0

4 years ago

Find the standard equation of the circle with center (5, -3

Mrac [35]

Answer:

○ C

Explanation:

Accourding to one of the circle equations, $\displaystyle (x - h)^2 + (y - k)^2 = r^2,$ the centre of the circle is represented by $\displaystyle (h, k).$ Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:

Pythagorean Theorem

$\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = r^2 \hookrightarrow 36 + 64 = r^2 \hookrightarrow \sqrt{100} = \sqrt{r^2} \\ \\ \boxed{10 = r}$

Sinse we are dealing with length, we only desire the NON-NEGATIVE root.

Distanse Equation

$\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-5 - 3]^2 + [3 + 3]^2} = r \hookrightarrow \sqrt{[-8]^2 + 6^2} = r \hookrightarrow \sqrt{64 + 36} = r; \sqrt{100} = r \\ \\ \boxed{10 = r}$

Sinse we are dealing with distanse, we only desire the NON-NEGATIVE root.

I am joyous to assist you at any time.

5 0

2 years ago