<span> i'm going to be slightly extra careful in showing each step. specific, ln [n / (n+a million) ]= ln n - ln(n+a million). So, we've sum(n=a million to infinity) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) [ln n - ln(n+a million)] = lim(ok--> infinity) (ln a million - ln 2) + (ln 2 - ln 3) + ... + (ln ok - ln(ok+a million)) = lim(ok--> infinity) (ln a million - ln(ok+a million)), for the reason that fairly much all the words cancel one yet another. Now, ln a million = 0 and lim(ok--> infinity) ln(ok+a million) is countless. So, the sum diverges to -infinity. IM NOT COMPLETELY SURE
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There r 2 ways to do this....percent to decimal
(1) u can divide by 100.....289/100 = 2.89
(2) u can move the decimal 2 spaces to the left....2.89
just so u know ... decimal to percent
(1) multiply by 100
(2) move decimal 2 spaces to right
Answer:
1759.52cm^3
Step-by-step explanation:
Given data
Cylinder E
h = 30 cm and
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*30
V= 3.142*16*30
V=1508.16 cm^3
Cylinder F
h=5 cm
r = 4 cm
The expression for the volume is
V= πr^2h
V= 3.142*4^2*5
V= 3.142*16*5
V=251.36 cm^3
Hence the total volume is
=251.36+1508.16
= 1759.52cm^3
Answer:
Correct choice is B
Step-by-step explanation:
In step 4 were proved that ![\triangle ABC\sim\triangle DEC.](https://tex.z-dn.net/?f=%5Ctriangle%20ABC%5Csim%5Ctriangle%20DEC.)
By definition, similar triangles have proportional lengths of corresponding sides. To the side AB corresponds side ED, to the side AC corresponds side DC and to the side BC corresponds side EC. Thus,
![\dfrac{AC}{DC}=\dfrac{BC}{EC}.](https://tex.z-dn.net/?f=%5Cdfrac%7BAC%7D%7BDC%7D%3D%5Cdfrac%7BBC%7D%7BEC%7D.)
The answer to the question is C.