<span>let y = sec^2 ( pi x )
y' = 2 sec ( pi x ) sec( pi x ) tan ( pi x ) pi
y' = 2pi sec^2 ( pi x ) tan ( pi x )
y''= 2pi sec^2 ( pi x ) * sec^2 ( pi x ) * pi + 2pi tan ( pi x ) * 2pi sec^2 ( pi x ) tan ( pi x )
y'' = 2 pi^2 sec^4 ( pi x ) + 4 pi^2 sec^2 ( pi x ) tan^2 ( pi x )</span>
Hey!
So you have a net of the figure. It's broken into several 2D shapes. What you an do it find the area of each shape and add it together.
Triangles:
A = (b*h)/2
A= (5 * 3) / 2
A = 15/2
same thing for the second one
15/2 * 2 = 15
Don't forget, there are 2 triangles so it's really 15 for both
Rectangles:
A=b*h
A= 7*5
A=35
A=7*5
A=35
A=3*7
A=21
35+35+21=91
Now add the sum of the area of the triangles and the sum of the area of the rectangles
91+15 = 106
106 is the surface area
Hope this helps!
Answer:

Step-by-step explanation:
Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.
Let altitude = y; solve for y:




Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).





Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

Change the equation to slope intercept form:
-5y=-x+10
y=1/5x-2
The y intercept is -2
59 is prime number so there's only 1 factor pair of 59
1 and 59
Answer
1 and 59